4x2 - 12x + 9 = 5; whence, 2x - 3 = ±√5, and 2x = 3 ±√5. Therefore, x = ½ (3 ±√5).
(2x - 5)(2x - 5) or (2x - 5) squared
2(2x^2 + 2x - 5)
(2x + 5)(4x2 - 10x + 25)
3x+5 = 2x+13 3x-2x = 13-5 x = 8
4x2 - 2x = 0
No.
4x2 - 12x + 9 = 5; whence, 2x - 3 = ±√5, and 2x = 3 ±√5. Therefore, x = ½ (3 ±√5).
4x2 + 12x + 5 = (2x + 1)(2x + 5).
4x2 + 12x + 5 = 4x2 + 2x + 10x + 5 = 2x(2x+1) + 5(2x+1) = (2x+1)(2x+5)
(2x+5)(2x+5)
(2x+5)(2x+1)
(2x - 5)(2x - 5)
(2x - 1)(2x + 5)
(2x - 5)(2x - 5) or (2x - 5) squared
The equation y = 4x^2 + 5 is a parabola
4x2+20x+25 (2x+5)^2