x = 10
x2 + 5x = 60 x2 + 5x + 25/4 = 60 + 25 / 4 (x + 5/2)2 = 265/4 x + 5/2 = (265/4)1/2 x = -5/2 ± √265 / 2 x = -(5 ± √265) / 2
You cannot solve 1 linear equation in 2 unknown variables. You need at least two independent equations.
-5x + y = -12- 3x + 6y = -12Since both of expressions have a value of -12, their sum is - 24. This is true only whenx = 20/9 and y = -8/9.-5x + y = -12y = 5x - 12- 3x + 6y = -12-3x + 6(5x - 12) = -12-3x + 30x - 72 = -1227x = 60x = 60/27x = 20/9y = 5x - 12y = 5(20/9) - 12y = 100/9 - 12y = (100 - 108)/9y = -8/9
4507 5267 - 500 - 200 - 60 = 4507
9x = 60x = 60/9 = 6 2/3 (or 6.67)
-10
(3)(2)(2)5x=60 12(5x)=60 12(5x)/12=60/12 5x=5 x=1
sixty is equal to 10 plus 50, and as 10 equals 50, and 50 equals 79, then it would be fair to assume that 60 equals 50 plus 79, which is 129.
Doesn't have integer roots. Quadratic formula gives roots as 3.71 and -5.38.
x = 10
-10 x -6 = 60 60 + -12 = 48
300 !
275
2X + 50 = 5X - 10 subtract 2X from each side 50 = 3X - 10 add 10 to each side 60 = 3X divide each side by 3 20 = X check 2(20) + 50 = 5(20) - 10 40 + 50 = 100 - 10 90 = 90 checks
65
5x - 60 = 5*(x - 12)