A= {x/x is a counting number less than 6} A={1,2,3,4,5} B={x/x is counting number than 5 but less than or equal to 10} B={6,7,8,9,10} -Mina Bacalla-
6+b Should it not be: b>6
b-7
The number could be anything less than 6
I believe that's usually treated as an axiom, meaning you don't prove it.
b-6
a is 6 less than d.
b-4 expression example b = 10 so b-4 = 6
A plus b plus c equals d. A is the largest answer b is the smallest answer and d is less than 6?''
You already said the answer that b is less than c
Two integers A and B are graphed on a number line. If A is less than B is A always less than B?
if a is less than and not equal to b, it is written a < bIf a is less than or equal to b, it is written a ≤ b
"Less than" is an asymmetric relationship since if a less than b then b is not less than a. That is, (a < b) => ¬ (b < a).
You can use arrows to show that one number is less than another: if a is less than b, you can symbolize that as a<b. If a is greater than b, you can write it as a>b.
The less than symbol looks like this: < This is where A < B ; A is less than B
a < b < c So, neither a nor b is greater than c.
No. B is either more or less than A therefore B isn't the same as A.