Oh, dude, that's just a fancy way of saying 6x^2 - x. So, like, you're just subtracting x from 6 times x squared. It's like if you had 6 apples and someone took one away, you'd have 5 apples left. So, the answer is 6x^2 - x.
That factors to (x - 5)(x - 1)
x^2-4x/x^2-6x+8 = x(x-4)/(x-2)(x-4) = x/(x-2)
{-1,7}
(x-1)(x-5)=x^2-6x +5 Because it is negative 5, I dont see an answer.
x^2 + 6x + 9 cannot be simplified further. If x^2 + 6x + 9 = 0 then we can solve for x. x^2 + 6x + 9 can be broken into a binomial: (x+3)(x+3), which then gives us x = -3.
x2 - 6x - 27 = (x-9)(x+3)
First, factorising, we get: x2 - 6x - 16 = (x - 8)(x + 2). Then, (x2 - 6x - 16) / (x - 8) = x + 2.
x-8
(6x - 1)(6x - 1)
That factors to (x - 5)(x - 1)
x^2-4x/x^2-6x+8 = x(x-4)/(x-2)(x-4) = x/(x-2)
(3x^(2) - 6x) / 3x Factor the numerator Hence 3x(x -2) / 3x Cancel down by '3x' Hence x -2 is the answer.
(x^2 - 2)(x - 2)(x + 2)
(x - 3)(x^2 + 6)
It is: (3x+4)(2x-3) when factored
{-1,7}
(x-1)(x-5)=x^2-6x +5 Because it is negative 5, I dont see an answer.