First, factorising, we get:
x2 - 6x - 16 = (x - 8)(x + 2).
Then,
(x2 - 6x - 16) / (x - 8) = x + 2.
x-8
(3x2 - 6x)/3x = 3x(x-2)/3x = x-2, for x<>0
{-1,7}
When factored it is: (6x-1)(6x+1)
-116
The factors of 6x^2 = 23x = 4 are (6x + 1)(x - 4)
x = 0,1
x2 - 6x - 27 = (x-9)(x+3)
x^2-4x/x^2-6x+8 = x(x-4)/(x-2)(x-4) = x/(x-2)
(3x + 2)(2x - 3)
3x(6x - 1)
It is: (2x+3)(3x-8) when factored