x2+7x-8 = (x-1(x+8)
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x2 + 7x - 8 = (x + 8)(x - 1)
7x-5x=8 2x=8 x=4
9x-4 = 7x+8 9x-7x = 8+4 2x = 12 x = 6
Algebraic constants are numbers with no variable (7x+7x+8=14x+8. The constant would be 8)
Presumably this is an equation in which the value of x is to be found. 7x+8 = 4x-10 7x-4x = -10-8 3x = -18 x = -6