x2+7x-8 = (x-1(x+8)
x2 - 7x = 8 x2 - 7x - 8 = 0Now find two numbers that multiply to equal -8, and add to equal -7.(1) * (-8) = -8(1) + (-8) = -7(x+1)(x-8) = 0 This is the factored form of x2 - 7x = 8You can then solve the equation if necessary, and get:x = -1 or x = +8
To solve the equation x^2 + 7x - 80, you would get x = 6.105 and x = -13.105, I believe.
7x-5x=8 2x=8 x=4
9x-4 = 7x+8 9x-7x = 8+4 2x = 12 x = 6
x2+7x-8 = (x-1(x+8)
Assuming that what you're looking for is the values of x: x2 + 7x = 8 x2 + 7x - 8 = 0 (x + 8)(x - 1) = 0 x is equal to either -8 or 1.
x2+7x-8 = (x-1(x+8)
x2+7x-8 = (x-1(x+8)
If: y = x2-7x+8 and y = -x2+9x-6 Then: x2-7x+8 = -x2+9x-6 So: 2x2-16x+14 = 0 => x2-8x+7 = 0 Therefore: x = 1 and x = 7 By substitution: x =1, y = 2 and x = 7, y = 8 Points of intersection: (1, 2) and (7, 8)
x2 - 7x - 8 = 0 (x + 1)(x - 8) = 0 x ∈ {-1, 8}
x2 - 7x = 8 x2 - 7x - 8 = 0Now find two numbers that multiply to equal -8, and add to equal -7.(1) * (-8) = -8(1) + (-8) = -7(x+1)(x-8) = 0 This is the factored form of x2 - 7x = 8You can then solve the equation if necessary, and get:x = -1 or x = +8
4x + 8 + 7x + 12 = 11x + 20
7x + y = 8 Subtract 7x from each side of the equation: y = -7x + 8
7x + 8 = 36 - 8 = - 8 -------------- 7x = 28 7x/7 = 28/7 x = 4
8+7x = 20+3x 7x-3x = 20-8 4x = 12 x = 3
7x-5x=8 2x=8 x=4