91=13x7
Its a prime number and cant be factored except by itself or one
13x = 91To solve for x, divide both sides of the equation by 13.13x/13 = 91/13x = 91/13 = 7
80 is the answer
Yes
80% of 91 = 72.8
91% of 80 = 0.91 x 80 = 72.8
There are 1609.344 metres in one mile. Therefore, 4135 miles is equal to 4135 x 1609.344 = 6654637.44 metres.
91 = 13 x 7 80 = 2 x 2 x 2 x 2 x 5 Since 91 and 80 have no factors in common other than 1, the GCF of 80 and 91 is 1.
composite
5800
Not by itself. In the sequence 80, 85, 91, 99 106... 91 is the median.
N. H. 4, Village Teppada Begur, Nelamangala, Bangalore 600 02, Karnataka p: +(91)-(80)-27733251 f: +(91)-(80)-7733252 N. H. 4, Village Teppada Begur, Nelamangala, Bangalore 600 02, Karnataka p: +(91)-(80)-27733251 f: +(91)-(80)-7733252 N. H. 4, Village Teppada Begur, Nelamangala, Bangalore 600 02, Karnataka p: +(91)-(80)-27733251 f: +(91)-(80)-7733252 N. H. 4, Village Teppada Begur, Nelamangala, Bangalore 600 02, Karnataka p: +(91)-(80)-27733251 f: +(91)-(80)-7733252 N. H. 4, Village Teppada Begur, Nelamangala, Bangalore 600 02, Karnataka p: +(91)-(80)-27733251 f: +(91)-(80)-7733252 N. H. 4, Village Teppada Begur, Nelamangala, Bangalore 600 02, Karnataka p: +(91)-(80)-27733251 f: +(91)-(80)-7733252 N. H. 4, Village Teppada Begur, Nelamangala, Bangalore 600 02, Karnataka p: +(91)-(80)-27733251 f: +(91)-(80)-7733252
ANSI 4135
No
The Bold and the Beautiful - 1987 1-4135 was released on: USA: 22 September 2003
60 63 68 80 91 91 100? First place the terms in Rank Order. NB This has already be done. For the median you take the ABSOLUTE middle term. Which in this case is '80'. Notice there are three terms to the left of '80' and three terms to the right. NNB This is good for an odd number of terms. When there is an even number of terms , you take the middle two terms . Add then together and divide by '2'. Do for the above set of terms , we add an eighth term , say '110'. Then 60 63 68 80 91 91 100,110. We take the two middle terms '80' & '91'(80+ 91) / 2 = 85.5 ; rthis is the median term.