3*3 + 3 + 3/3 = 9 + 3 + 1 = 133*3 + 3 + 3/3 = 9 + 3 + 1 = 133*3 + 3 + 3/3 = 9 + 3 + 1 = 133*3 + 3 + 3/3 = 9 + 3 + 1 = 13
27 3 to the power of 3 3 x 3 x 3 (3 x 3) x 3 9 x 3 27
Y^3(Y^3-Y)=???We know Y=3 so this, Y^3(Y^3-Y) now looks like this..3^3(3^3-3)For the outsidewe know 3^3=27Ex. 3x3x3=27Break Down3x3=9x3=27So from Y^3(Y^3-Y)we went to 3^3(3^3-3)to this 27(27-3)Now subtract 27-3=24to get you final X27(24)= or 27*24= 648Steps...Y^3(Y^3-Y)Y^3(Y^3-Y)3^3(3^3-3)27(27-3)27(24)= or 27*24= 648
Where Y = 2x-3, the output for x = 3 is Y = 3. 2x - 3 = 2(3)-3 = 6-3 = 3
0 - 0 - 3 = -3
The conjugate base of HPO4^2- is PO4^3-.
Fe2(HPO4)3
This compound is iron(III) hydrogenphosphate.
No, the equation is: HPO4-2 → H+ + PO4-3 The HPO4-2 and PO4-3 are conjugate acid base pairs.
the pH of HPO4-2 is 5.
This compound is iron(III) hydrogenphosphate.
The conjugate base of HPO4 is PO43-
HPO4-2 is an acid and a base. however when mixed with NO2- (Base) then HPO4-2 must be an acid.
Fe2(HPO4)3Four different species! Will need number atoms every species as protons vary. What a lot of work! In order.134 grams Fe2(HPO4)3 (1 mole Fe2(HPO4)3/399.634 grams)(2 mole Fe/1 mole Fe2(HPO4)3)(6.022 X 1023/1 mole Fe)= 4.04 X 1023 atoms iron * 26 protons = 1.05 X 1025 protons iron-----------------------------------------------------======================-----------------------------------------------==============134 grams Fe2(HPO4)3/399.634 grams)(12 mole O/1 mole Fe2(HPO4)3)(6.022 X 1023/1 mole O)= 2.42 X 1024 atoms oxygen * 8 protons = 1.94 X 1025 protons oxygen--------------------------------------------------------====================I think you can add all the bold numbers to get total.
That's not a stable compound. If you meant HPO4--, it can be formed by either the reduction of the PO43- ion or oxidation of the H2PO4- ion.
hydrogen phosphate ion.
HPO4 2-