Hpo2- +f-
5
2 to the power of 4 is an expression, it is not an equation.
The equation is x = 2
Assuming that the 2 in "5x2" is a power (5x2), then no, this is not a linear equation. It is a parabolic equation.
The conjugate base of HPO4 2- is H2PO4 -, which results from the loss of one hydrogen ion (H+) from the dihydrogen phosphate ion.
To write the conjugate base of HPO4 2-, simply remove one hydrogen ion (H+) from the molecule. The formula for the conjugate base would be H2PO4 -.
That's not a stable compound. If you meant HPO4--, it can be formed by either the reduction of the PO43- ion or oxidation of the H2PO4- ion.
The conjugate acid of H2PO4- is H3PO4. When H2PO4- donates a proton, it forms the conjugate acid H3PO4.
The conjugate base for HPO4^2- is H2PO4^-.
The conjugate base of HPO4^-2 is PO4^-3 because when HPO4^-2 loses a single hydrogen ion in a reaction, it forms PO4^-3.
'Conjugate' means ONE proton more (acid) or less (base) than the described acid or base respectively:So the conjugate acid of PO43- (phosphate) is HPO42- (monohydrogen phosphate)
Calcium phosphate is Ca3(PO4)2. It is a combination of the Ca2+ ion with the PO43- ion.
The equation for the phosphate buffer system is HPO4^2- + H2O ↔ H2PO4^- + OH^-. The system involves the dihydrogen phosphate ion (H2PO4^-) acting as a weak acid and the hydrogen phosphate ion (HPO4^2-) acting as its conjugate base, helping to maintain pH stability in biological systems.
There are two reaction equations for phosphate ion and water. They two equations are: i) HPO4 2- + H2O => H3O+ + PO4 3- ii) HPO4 2- + H2O => OH- + H2PO4 -
HPO4^2- is an acidic species as it can donate a proton (H+) in solution. NO2, on the other hand, can act as a base by accepting a proton. When mixed together, they can form a reaction where HPO4^2- donates a proton to NO2, leading to the formation of H2PO4^- and NO2^-.
hydrogen phosphate ion.