Hpo2- +f-
2 to the power of 4 is an expression, it is not an equation.
5
The equation is x = 2
Assuming that the 2 in "5x2" is a power (5x2), then no, this is not a linear equation. It is a parabolic equation.
The conjugate base of HPO4 2- is H2PO4 -, which results from the loss of one hydrogen ion (H+) from the dihydrogen phosphate ion.
To write the conjugate base of HPO4 2-, simply remove one hydrogen ion (H+) from the molecule. The formula for the conjugate base would be H2PO4 -.
HPO4, or hydrogen phosphate, is formed by the partial deprotonation of phosphoric acid (H3PO4). When one of the protons in phosphoric acid is removed, it forms the HPO4 ion.
The conjugate acid of H2PO4- is H3PO4. When H2PO4- donates a proton, it forms the conjugate acid H3PO4.
The conjugate base for HPO4^2- is H2PO4^-.
The conjugate base of HPO4^-2 is PO4^-3 because when HPO4^-2 loses a single hydrogen ion in a reaction, it forms PO4^-3.
'Conjugate' means ONE proton more (acid) or less (base) than the described acid or base respectively:So the conjugate acid of PO43- (phosphate) is HPO42- (monohydrogen phosphate)
The equation for the phosphate buffer system is HPO4^2- + H2O ↔ H2PO4^- + OH^-. The system involves the dihydrogen phosphate ion (H2PO4^-) acting as a weak acid and the hydrogen phosphate ion (HPO4^2-) acting as its conjugate base, helping to maintain pH stability in biological systems.
Calcium phosphate is Ca3(PO4)2. It is a combination of the Ca2+ ion with the PO43- ion.
In water, H2PO4 dissociates into H+ and HPO4^2- ions, forming the equilibrium reaction: H2PO4^- ⇌ H+ + HPO4^2-
HPO4^2- is an acidic species as it can donate a proton (H+) in solution. NO2, on the other hand, can act as a base by accepting a proton. When mixed together, they can form a reaction where HPO4^2- donates a proton to NO2, leading to the formation of H2PO4^- and NO2^-.
hydrogen phosphate ion.