PF 1 & PF2 stands PRIME FACTORIZATION
If p = 2s + 5, then s = (p-5)/2 or 1/2 (p-5) --- p = 2s +5 p-5 = 2s (p-5)/2 = s
No, it would be 62. The equation is: f(n) = 2(f(n - 1) + 1), with f(0) = 0. So f(5) = 2(30 + 1) = 62
Let f(X)=2X2+6X+3 So f(-p)=f(2q) or 2p2-6p+3=8q2+12q+3 or p2-3p=4q2+6q or p2-4q2=3p+6q or (p+2q)(p-2q)=3(p+2q) so p-2q=3
f(x) = 2/x = 2x^-1 so dy/dx = -2x^-2 = -2/x² f(x) = 2/x This can be re-written as f(x) = 2x^-1 according the to the laws of exponents. Now, we just take the derivative normally: f(x) = 2x^-1 f ' (x) = -1 × 2x^(-1-1) = -2x^-2 The above can be re-written in quotient form as f ' (x) = -2/x²
1/2(9+p)=p-3
1[+] Helium‎ (5 C, 1 P, 59 F)2[+] Neon‎ (3 C, 1 P, 56 F)3[+] Argon‎ (2 C, 1 P, 25 F)4[+] Krypton‎ (2 C, 1 P, 18 F)5[+] Xenon‎ (2 C, 1 P, 19 F)6[×] Radon‎ (1 P, 18 F)7[×] Ununoctium‎ (1 P, 9 F)
For a general Lp space: In the notation of Lp norms: Let f and g be Lp functions, then: f+gp <= fp+gp Specifically for p=2, using integrals, we have (where "S" means integral): (S(f+g)2)1/2 <= (S(f)2)1/2+(S(g)2)1/2 and again, replacing p with 2 will yield the definition is a general Lp space.
Halifax f-p- - 1994 Words Without Music 1-2 is rated/received certificates of: USA:R
One tenth (1/10) = 10%. Think of Percent as 'per hundred', so to find a percentage, do this: F = P% = P/100, where F is the fraction, and P is the percentage.You are given F, so solve for P. Rearrange and you have P = 100 x F, so we have P = [100 x (1/10)] = 10.
1.What is the formula for a proportionp = n / f2. p = (f / 100) * n3. p = f / n4. p = (f / n) * 100
Call F the final amount and P the principal. Then F = P(1+i)n F/(1+i)n = P
T=Period F=frequency T=1/F Period=1/F
Two for the price of one
∫ f'(x)/( q2f(x)2 - p2) dx = [1/(2pq)ln[(qf(x) - p)/(qf(x) + p)]
F-P-1 - 1933 is rated/received certificates of: USA:Passed (National Board of Review)
∫ f'(x)/(p2 + q2f(x)2) dx = [1/(pq)]arctan(qf(x)/p)
Infinity.because the distance of object from mirror"p" and the distance from image to mirror"q" are equal,so by using formula 1/f=1/p+1/q we can find the answer as the image of plane mirror is virtual,so"q" is taken negative,so putting values 1/f=1/p-1/p(bcz p=q) 1/f=0 f=1/0 and any thing divided by zero is infinity.