Let
f(X)=2X2+6X+3
So f(-p)=f(2q)
or 2p2-6p+3=8q2+12q+3
or p2-3p=4q2+6q
or p2-4q2=3p+6q
or (p+2q)(p-2q)=3(p+2q)
so p-2q=3
226186081502
10
real and unequal
10 to the negative 18th power is equal to 1 divided by 10 to the 18th power. In other words, it is equal to 0.000000000000000001, or 1 divided by 1 followed by 18 zeros. This number is a very small decimal fraction, indicating a minute value.
No. Not if there are an even number of observations and the middle two values are unequal.
When a number is divided by 32, the remainder can range from 0 to 31, as the remainder can never be greater than the divisor. Therefore, the greatest value the remainder may have is 31.
24
The remainder is always 31 or less.
0.6667
68686868
The remainder is the number that is left over after the initial value has been divided as much as it can. If any numbers greater than 48 were present as a remainder, then these could be divided further into 48. If 48 is present as the remainder, then this can be divided by 48 to give 1, leaving no remainder. Thus, the largest possible remainder if the divisor is 48 is 47.
226186081502
The value of x must be 23 because 19*23/17 or 437/17 = 25 with a remainder of 12
273
unequal
100 divided by 25 times 64 = 256
If the remainder must be an integer value, then the largest remainder you can have from any equation when dividing by 12 is a remainder of 11. Example: (23 / 12 = 1 R11) 12 goes into 23 one time, and there's 11 left over. If there was more than 11, such as (24 / 12), then the answer would be 2 with no remainder.