answer is p/5. problem: {[(p^2)-3p]/[(p^2)-6p+9]}/{20/(4p-12)}
-2p squared
p2 X p2 = p4or p X p X p X p = p4
2
p2 + p2 + p3 = 2p2 + p3 because you can add the two variables that match, while you leave the different variable alone.
p^3 ÷ p^2 = p^(3-2) = p^1 = p
answer is p/5. problem: {[(p^2)-3p]/[(p^2)-6p+9]}/{20/(4p-12)}
∫ f'(x)/( q2f(x)2 - p2) dx = [1/(2pq)ln[(qf(x) - p)/(qf(x) + p)]
∫ f'(x)/(p2 + q2f(x)2) dx = [1/(pq)]arctan(qf(x)/p)
p2 + 9p + 18/ p + 6(p + 6)(p + 3)/ p + 6(p + 6)(p + 3)/ p + 6p + 3
The corect answer would be pie divided by the square root of 2342 squared. :P your welcome.. -Savanah Markee
Well, darling, if we're talking math, P squared plus P squared equals 2P squared. It's as simple as that. So, next time you're trying to impress someone with your algebra skills, just remember this little gem.
p^2 x p^2 = p^4 p^2 + p^2 = 2p^2
-2p squared
p2 X p2 = p4or p X p X p X p = p4
p^2(p squared)
P cubed