P cubed
(bc)2
b to the fourth power
pi times the radius squared pi r squared
0 squared is 0. Zero times zero equals zero.
4x4=16 or 2^4=16
p2 X p2 = p4or p X p X p X p = p4
(6p)^2=36p^2
P^2 + p^2 cannot be simplified.
P squared = P*P. When divided by P, the equation becomes (P*P/P, and the answer is "P".
2 x 3 x 3 x p x p = 18p^2
p^2 x p^2 = p^4 p^2 + p^2 = 2p^2
-2p squared
p^2(p squared)
36 squared times 24 squared is equal to 746,496.
P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.
p2-2p = p(p-2) when factored
s = p^2 - 5 *also, p = sqrt (s+5)