This is a system of equations:-x + 5y = 10-5x + 2y = 27Multiply the first equation by 5.-5x + 25y = 50Subtract the 2 equations:23y = 23Solve:y = 1-x + 5(1) = 10-x = 5x = -5Thus, the ordered pair is (-5, 1).
3x+2 = 5x so 2x = 2 and hence x = 2/2 = 1
Y=-1/2(x)
3x + 5x = 2x + 28x = 2x + 26x = 2x = (2/6) = 1/3
The 7x and the 5x are like terms. This means that you can add them up. Think about it, 7 x's plus 5x's equals 12x's. From there, you can divide 12 from both sides of the equation, and you will get that x = 2.
8x-7 plus 2x equals 6 plus 5x plus 2?
If: y = -5x+3 then the points are (2, -7) and (6, -27)
f(x)=5x+2
5x+2=x+10 5x-x=10-2 4x=8 x=2
DIE
Here is the work for that problem: 5x+ 2=12 5x= 12-2 5x=10 x= 2
-5x -23 + 3x = -27 Combine like terms: -2x - 23 = -27 Add 23 to each side: -2x = -4 Divide each side by -2: x = -4/-2 x = 2
x=6Solution:x + 2x + 14 = 5x + 214 - 2 = 5x - 3x12 = 2xx = 12/2 = 6
If Y=5x + 2 and x is 5 then Y= 5*5 +2, using order of operations, you get Y=25 +2 Y= 27
5x+2=2x-10 x=-4
5x + 2 = 22 5x = 22 - 2 5x = 20 5x/5 = 20/5 x=4
x = zero