y/5
6(4+y)
18• 6-y
6(n + y)
y < 18 x 6
When multiplying powers, you add them! y4 times y6 = y10. Try it with y = 2: 2 to the fourth = 16, 2 to the sixth = 64 16 x 64 = 1024 = 2 to the tenth.
y < 18*6y < 18*6y < 18*6y < 18*6
X = 4(6-y)
Algebraic expressions are useful for translating problems into the language of mathematics. An algebraic expression for the problem "6 times the sum of 4 and y" would be: 6(4+y) = 24 + 6y.
(9) · (x) · (2/3) · (y) = 6 x y
There is some ambiguity in the statement, which really requires parentheses to indicate which operation should be done first. So, four less than (y times 6) is written as 6y - 4, but (four less than y) times 6 is written as 6(y - 4). These quantities are quite different. For example, suppose that y = 5. Then, 6y - 4 works out to be 30 - 4 = 26. In comparison, 6(y - 4) = 6(5 - 4) = 6(1) = 6.
6y + 1 = 19 Therefore, 6y = 18 y = 18/6 y = 3