6(4+y)
y = 6 - 4 = 2, thus 3y = 3 x 2 = 6
4(y+1)
10
2x + 4 = y ...............2x + 4 = y ....................2x + 4 = y .............2*(-6)+ 4 = y x - y = 2 .......<=> ...x - 2x - 4 = 2 .....<=> ...x = -6......... <=>.... x = -6 ..............<=> y = - 8 x = - 6
6(4+y)
It could be: 6x+y+4
To find 4 times the sum of y and 7, you first calculate the sum of y and 7, which is y + 7. Then, you multiply this sum by 4 to get the final result. Therefore, the expression for 4 times the sum of y and 7 is 4(y + 7), which simplifies to 4y + 28.
5(x^2 + y)
6(n + y)
y = 6 - 4 = 2, thus 3y = 3 x 2 = 6
The equation: 4 - (6 + X) = Y For every different number X there is a different Y.
Call your number 10x + y. x = y + 2 and 10x + y = 4 + 6(x + y) Substitute y + 2 for x: 10(y + 2) + y = 4 + 6((y + 2) + y) This simplifies to 10y + 20 + y = 4 + 6y + 12 + 6y, ie 20 - 16 = 12y - 11y so y = 4 and x = 6 Your number is 64, which is indeed 4 more than the sum of its digits.
Y = 4 (x+8)
8 + 6y
X = 4(6-y)
4 + y.