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What is the solution of a 5a-5 equals 7 plus 2a?
5a - 5 = 7 + 2a ( subtract 2a from both sides) 3a - 5 = 7 (add 5 to both sides) 3a = 12 ( divide both sides by 3) a = 4
7a plus 4 equals 5a plus 7?
7a + 4 = 5a + 7 7a = 5a + 3 2a = 3 a = 3/2
How do you factor 5a3-25a2 plus 15a equals?
5a(a(a-5)+3)
What is 9a plus 21 equals?
9a+21 3(3a+7)
How do you solve 3a plus 4 equals 4a-3?
3a + 4 = 4a - 3 4 = a -3 (subtract 3a from each side) 7 = a (add 3 to both sides) a = 7
What is the answer to 5a plus 1 equals a-3?
Answer to: 5a + 1 = a - 3a = -1
What is the value of a in 13a - 6 plus a equals 5a plus 3 plus 3a?
13a - 6 + a = 5a + 3 + 3a 13a + a - 5a - 3a = 3 + 6 6a = 9 6a/6 = 9/6 a = 3/2
What is the answer to a plus b plus c equals 180 b equals 3a c equals 5a?
a + b + c = 180 b = 3a c = 5a Substituting the values of b and c into the first equation. a + 3a + 5a = 180 or 9a = 180 so that a = 20 then b = 3a = 3*20 = 60 and c = 5a = 5*20 = 100
What is -8a plus 3a?
-8a + 3a = (-8 + 3)a = (5)a = 5a
What is the solution of a 5a-5 equals 7 plus 2a?
5a - 5 = 7 + 2a ( subtract 2a from both sides) 3a - 5 = 7 (add 5 to both sides) 3a = 12 ( divide both sides by 3) a = 4
7a plus 4 equals 5a plus 7?
7a + 4 = 5a + 7 7a = 5a + 3 2a = 3 a = 3/2
3a plus 21 equals 30 what is a?
a = 3
What is the summation notation of quantity of 3a plus 4a plus 5a plus 6a to the third power?
It is not clear whether the question is 3a + 4a + 5a + 6a^3 which would be 12a + 6a^3 or 3a + 4a + 5a + (6a)^3 = 12a + 216a^3 or (3a + 4a + 5a + 6a)^3 = 5832*a^3 But none of these really require summation notation!
What is -7a plus 2a plus 9 equals 24?
-7a+2a+9 is also -5a+9. -5a+9=24. -5a=15. a=-3.
How do you solve a squared minus 4 over 2 plus 6a times 3 plus 9a over a squared plus 5a plus 6?
In order to solve something, there needs to be an equation. If I have read your equation right you have: (a² - 4)/(2 + 6a) x (3 + 9a)/(a² + 5a + 6) This looks like it needs to be simplified. There are two fractions being multiplied, so multiply the numerators and denominators together, giving: (a² - 4)/(2 + 6a) x (3 + 9a)/(a² + 5a + 6) = ((a² - 4)(3 + 9a)) / ((2 + 6a)(a² + 5a + 6)) Now, simplify the polynomials to remove the squared terms and any common factors: a² - 4 = (a - 2)(a + 2) 2 + 6a = 2(1 + 3a) 3 + 9a = 3(1 + 3a) a² + 5a + 6 = (a + 3)(a + 2) Giving: ((a² - 4)(3 + 9a)) / ((2 + 6a)(a² + 5a + 6)) = ((a + 2)(a - 2)3((1 + 3a))/(2(1 + 3a)(a + 3)(a + 2)) This can now be simplified by cancelling out equivalent terms, giving: ((a + 2)(a - 2)3(1 + 3a))/(2(1 + 3a)(a + 3)(a + 2)) = ((a - 2)3) / (2(a+3)) = 3(a - 2) / 2(a + 3) = (3a - 6) / (2a + 6)
How do you factor 3a2-16a plus 5?
3a2 - 16a + 5 = 3a2 - 15a - a + 5 = 3a(a -5) - 1(a -5) = (3a - 1)(a - 5)
Factorising- 3a plus 9 equals?
3a + 9 =3X(a + 3)
