x = b/(a + c)
B squared equals c squared minus a squared then to find B take the square root of you answer for b squared
(a + b + c)3 = a3 + b3 + c3 + 3(a2b + ab2 + b2c + bc2 + ca2 + ac2) + 6abc
49 + c units
a + b + c = 180 b = 3a c = 5a Substituting the values of b and c into the first equation. a + 3a + 5a = 180 or 9a = 180 so that a = 20 then b = 3a = 3*20 = 60 and c = 5a = 5*20 = 100
a - b = c -(a - b) = -c b - a = -c
x(-b)=m(x-c)
complement of c
C minus B equals AB
x = b/(a + c)
well if the coefficient of a times the negative reciprical of b equals 4.33 then if you add all of them they should be able to fit in as themselves int the equation: x=-b(plus or minus) (the sqare root of:(b)(b)+-4ac) all divided by 2a, the basic quadratic equation its elementery me dear lad
A=0 b=0 c=0
When b is zero.
B squared equals c squared minus a squared then to find B take the square root of you answer for b squared
(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c
its B
It equals b times c.