7 times 5
It is: 5k-7
To express "7 times a number increased by 4" mathematically, you would write it as 7x + 4, where x represents the unknown number. This expression indicates that you multiply the number by 7 and then add 4 to the result. So, if the number is 5, the expression would be 7(5) + 4 = 35 + 4 = 39.
The expression (x+5)(x-7) = x^2 -2x -35
3(y+7)
It can be: 7-4x as an algebraic expression
To express (2^{-5} \times 28) as an exponential expression, we can first rewrite 28 in terms of base 2. Since (28 = 4 \times 7 = 2^2 \times 7), we can substitute this into the expression: [ 2^{-5} \times 28 = 2^{-5} \times (2^2 \times 7) = 2^{-5 + 2} \times 7 = 2^{-3} \times 7. ] Thus, the exponential expression is (2^{-3} \times 7).
(5 × 7) ÷ 5 = 7
The expression ( 7(m + 5)21 ) can be simplified by first distributing the 7 and the 21. This gives us ( 7 \times 21 \times (m + 5) = 147(m + 5) ). Thus, the expression simplifies to ( 147(m + 5) ).
To rewrite (2 \times 5 \times 5 \times 7) using exponents, you can express the repeated multiplication of the number 5 as (5^2). Therefore, the expression can be rewritten as (2 \times 5^2 \times 7).
It is: 5k-7
To solve the expression (15x(7-7)(5 \times 2)), first simplify the term inside the parentheses: (7 - 7 = 0). This means the entire expression becomes (15x \times 0 \times (5 \times 2)). Since any number multiplied by zero is zero, the final result is (0).
A numerical expression sentence is a statement that represents a mathematical relationship using numbers and operations. For example, "The sum of 7 and 5 is 12" can be expressed as the numerical expression (7 + 5 = 12). Another example could be "Twice the number of apples, 3, gives you 6," which translates to the expression (2 \times 3 = 6).
To combine the integers 2, 3, 5, and 7 in two different ways, we can use addition and multiplication. First expression: ( (2 + 3) \times (5 + 7) = 5 \times 12 = 60 ). Second expression: ( (2 \times 5) + (3 \times 7) = 10 + 21 = 31 ). Thus, the results of the expressions are 60 and 31, respectively.
The expression (2 \times 2 \times 2 \times 5 \times 5 \times 7) can be written in exponent form as (2^3 \times 5^2 \times 7^1). This indicates that 2 is multiplied three times, 5 is multiplied two times, and 7 is multiplied once.
The expression (2^5 \times d^7) simplifies to (32 \times d^7), since (2^5) equals 32. Therefore, the final result is (32d^7).
-38
The product of 7 and 5 = 35