7 times 5
It is: 5k-7
To express "7 times a number increased by 4" mathematically, you would write it as 7x + 4, where x represents the unknown number. This expression indicates that you multiply the number by 7 and then add 4 to the result. So, if the number is 5, the expression would be 7(5) + 4 = 35 + 4 = 39.
The expression (x+5)(x-7) = x^2 -2x -35
3(y+7)
It can be: 7-4x as an algebraic expression
(5 × 7) ÷ 5 = 7
The expression ( 7(m + 5)21 ) can be simplified by first distributing the 7 and the 21. This gives us ( 7 \times 21 \times (m + 5) = 147(m + 5) ). Thus, the expression simplifies to ( 147(m + 5) ).
To rewrite (2 \times 5 \times 5 \times 7) using exponents, you can express the repeated multiplication of the number 5 as (5^2). Therefore, the expression can be rewritten as (2 \times 5^2 \times 7).
It is: 5k-7
To solve the expression (15x(7-7)(5 \times 2)), first simplify the term inside the parentheses: (7 - 7 = 0). This means the entire expression becomes (15x \times 0 \times (5 \times 2)). Since any number multiplied by zero is zero, the final result is (0).
The expression (2 \times 2 \times 2 \times 5 \times 5 \times 7) can be written in exponent form as (2^3 \times 5^2 \times 7^1). This indicates that 2 is multiplied three times, 5 is multiplied two times, and 7 is multiplied once.
-38
The product of 7 and 5 = 35
The expression (7 \times 7 \times 7) can be written in exponential form as (7^3). This is because the base (7) is multiplied by itself three times.
12
It is 7*256.
To solve the expression ( 60 \div 5(7-5) ), first calculate the parentheses: ( 7 - 5 = 2 ). Then, the expression becomes ( 60 \div 5 \times 2 ). Dividing ( 60 ) by ( 5 ) gives ( 12 ), and multiplying ( 12 ) by ( 2 ) results in ( 24 ). Therefore, the final answer is ( 24 ).