No. If you expand (a + b)2 you get a2 + 2ab + b2. This is not equal to a2 + b2
(2a + b)(a + 3b)
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
sqrt(a2 + b2) can't be simplified. Neither can (a2 + b2) .
(a + 2 - b) (a + 2 + b)
(a+b)2
No. If you expand (a + b)2 you get a2 + 2ab + b2. This is not equal to a2 + b2
b= 10
b = 14324.80366
(a+b)(a squared-ab+b squared)
The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.
a=b=3.60555
4
It simplifies to 5a+4 !
(2a + b)(a + 3b)
(b-4) squared