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What is a quadrant of 3 and negative 7?
(3 , -7) is in the fourth (IV) quadrant.
What are the four quadrants of a cartesian graph?
Quadrant I ( + , + ) Quadrant II ( - , + ) Quadrant III ( - , - ) Quadrant IV ( + , - )
What quadrant is -6 -5 lies in?
-1
How can you tell from a scatter plot whether 2 variables have a positive correlation a negative correlation or no correlation?
Suppose the scatter plot is of a variable X on the horizontal scale and Y on the vertical scale.Find the approximate middle of the x values and call it p.Find the approximate middle of the y values and call it q.Draw horizontal and vertical lines through the point with coordinates (p, q).If you know about quadrants, skip this paragraph. The two lines through the point (p,q) divide up the plane into 4 quadrants. Quadrant I is top right. Quadrant II is top left. Quadrant III is bottom left. Quadrant IV is bottom right.If the scatter plot is mostly in quadrants I and III the correlation is positive. If mostly in quadrants II and IV the correlation is negative. Otherwise the correlation is small.Remember, though, that 0 correlation does not mean no relation. y = x2 will have 0 correlation but it is a perfectly well defined relationship!Suppose the scatter plot is of a variable X on the horizontal scale and Y on the vertical scale.Find the approximate middle of the x values and call it p.Find the approximate middle of the y values and call it q.Draw horizontal and vertical lines through the point with coordinates (p, q).If you know about quadrants, skip this paragraph. The two lines through the point (p,q) divide up the plane into 4 quadrants. Quadrant I is top right. Quadrant II is top left. Quadrant III is bottom left. Quadrant IV is bottom right.If the scatter plot is mostly in quadrants I and III the correlation is positive. If mostly in quadrants II and IV the correlation is negative. Otherwise the correlation is small.Remember, though, that 0 correlation does not mean no relation. y = x2 will have 0 correlation but it is a perfectly well defined relationship!Suppose the scatter plot is of a variable X on the horizontal scale and Y on the vertical scale.Find the approximate middle of the x values and call it p.Find the approximate middle of the y values and call it q.Draw horizontal and vertical lines through the point with coordinates (p, q).If you know about quadrants, skip this paragraph. The two lines through the point (p,q) divide up the plane into 4 quadrants. Quadrant I is top right. Quadrant II is top left. Quadrant III is bottom left. Quadrant IV is bottom right.If the scatter plot is mostly in quadrants I and III the correlation is positive. If mostly in quadrants II and IV the correlation is negative. Otherwise the correlation is small.Remember, though, that 0 correlation does not mean no relation. y = x2 will have 0 correlation but it is a perfectly well defined relationship!Suppose the scatter plot is of a variable X on the horizontal scale and Y on the vertical scale.Find the approximate middle of the x values and call it p.Find the approximate middle of the y values and call it q.Draw horizontal and vertical lines through the point with coordinates (p, q).If you know about quadrants, skip this paragraph. The two lines through the point (p,q) divide up the plane into 4 quadrants. Quadrant I is top right. Quadrant II is top left. Quadrant III is bottom left. Quadrant IV is bottom right.If the scatter plot is mostly in quadrants I and III the correlation is positive. If mostly in quadrants II and IV the correlation is negative. Otherwise the correlation is small.Remember, though, that 0 correlation does not mean no relation. y = x2 will have 0 correlation but it is a perfectly well defined relationship!
Express the function 120 degree as function of an acute angle?
Example: Express sin 120⁰ as a function of an acute angle (an angle between 0⁰ and 90⁰).Solution:Each angle θ whose terminal side lies in quadrant II, III, or IV has associated with it an angle called the reference angle, alpha (alpha is formed by the x-axis and the terminal side).Since 120⁰ lies on the second quadrant, then alpha = 180⁰ - 120⁰ = 60⁰.Since sine is positive in the second quadrant, sin 120⁰ = sin 60⁰.Example: Express tan 320⁰ as a function of an acute angle.Solution:Since 320⁰ lies on the fourth quadrant, then alpha = 360⁰ - 320⁰ = 40⁰.Since tangent is negative in the fourth quadrant, tan 320⁰ = -tan 40⁰.
