If those are the dimensions of a rectangular block, you need to calculate the area of the six rectangles, and add them all up. In other words (and since there are two rectangles of each type):Area = 2 x 2 x 1.5 + 2 x 2 x 1 + 2 x 1.5 x 1
Assuming the dimensions given refer to the side lengths of a cuboid, the answer is 13 cm^2.
A cube has six square faces. This cubes faces are 2 x 2 ie 4cm2 so overall surface area is 24 cm2.
A cube has 6 faces each face is area 2x2 = 4 square cm surface area = 6 x 4 = 24 sq cm
1 side of square = 2cm area of square = side x side so, area= 2x2 = 4 cm^2
Area of a triangle = 0.5*base*height
2cm*2cm*2cm = 8cm3
Not enough information given.
30cm
34 cm
A cube has six square faces. This cubes faces are 2 x 2 ie 4cm2 so overall surface area is 24 cm2.
300cc
It is: 2+15+2+15 = 34cm
A cube has all sides of length 2cm. What is the surface area and volume of the cube?
Eight little cubes.
You need three measures of length to determine the surface area - the length, width and height.
112 cm squared
Mean = sum(X)/n = 15cm/5 = 3cm
Volume = 8 cm3 so each side = 2 cm So area of one face = 2cm * 2cm = 4 cm2 So total surface area (6 faces) = 6*4 cm2 = 24 cm2