are 48 m bola tha tumne 48 inches likh diya...
There would be an infinite number of rectangles possible
the answer is 12
One way is to use coins and trace 10 circles which may or may not overlap depending on the intersections of your sets. It does get messy with lots of them. Some people use rectangles instead since they are easier to draw when you have so many.
No. Many investigators have searched for such an example, but none have found it yet. According to all published research so far, two rectangles with the same area always have the same area. But the search goes on, in many great universities.
Infinite amounts.
are 48 m bola tha tumne 48 inches likh diya...
9
There is an infinite number that can have that perimeter
Providing that they are whole numbers: 1*11 , 2*10, 3*9, 4*8, 5*7, 6*6 and 7*5 cm
There would be an infinite number of rectangles possible
thare is only 1 differint rectangles
perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
the answer is 12
Depends what you are drawing on.
There are three possibilities.. 1 x 12... 2 x 6 & 3 x 4
Infinitely many. Select any number, L, such that 12 < L < 24. Let W = 24 - L. Then a rectangle with sides of length L cm and width W cm will have a perimeter of 48 cm. And since the choice of L was arbitrary, there are infinitely many possible values of L and thence infnitely many rectangles.