It depends what units you use for each side ! A 1cm x 15cm rectangle has a perimeter of 16cm. So does a 2cm x 4cm one ! If you start using millimetres, there are many more possibilities !
are 48 m bola tha tumne 48 inches likh diya...
There would be an infinite number of rectangles possible
the answer is 12
One way is to use coins and trace 10 circles which may or may not overlap depending on the intersections of your sets. It does get messy with lots of them. Some people use rectangles instead since they are easier to draw when you have so many.
No. Many investigators have searched for such an example, but none have found it yet. According to all published research so far, two rectangles with the same area always have the same area. But the search goes on, in many great universities.
Infinite amounts.
9
are 48 m bola tha tumne 48 inches likh diya...
There is an infinite number that can have that perimeter
thare is only 1 differint rectangles
There would be an infinite number of rectangles possible
Providing that they are whole numbers: 1*11 , 2*10, 3*9, 4*8, 5*7, 6*6 and 7*5 cm
perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
To find the number of different rectangles with a perimeter of 24 cm, we first use the formula for the perimeter ( P = 2(l + w) ), where ( l ) is the length and ( w ) is the width. Setting ( 2(l + w) = 24 ) simplifies to ( l + w = 12 ). The pairs of positive integers ( (l, w) ) that satisfy this equation are ( (1, 11), (2, 10), (3, 9), (4, 8), (5, 7), (6, 6) ). This results in 6 unique rectangles, considering length and width can be interchanged.
the answer is 12
Depends what you are drawing on.
There are three possibilities.. 1 x 12... 2 x 6 & 3 x 4