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12 x 5 x 20 ie 1200squnits.

I'm not convinced you can have such a hexagon, if the side is 10 then shouldn't the apothem have to be 5 root 3?

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Q: What is the Area of a regular hexagon with a base of 10 and an apothem of 20?
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Find the area of a regular hexagon with a base of 10 and an apothem of 12?

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What is the area of a regular hexagon with a side of 4 and an apothem of 3 46?

Easy. Since the side is the base and the apothem is the height of the triangle, multiply them and divide by two to get the area of the triangle. 3 * 3.46 = 10.38 /2 = 5.19. Then multiply by 6 to get the area of the hexagon. 5.19 * 6 = 31.14. You multiply by 6 because you can fit 6 regular triangles in a regular hexagon. We've already found the area of one regular triangle in the hexagon.


Hexagonal prism volume?

the formula to find the area of any prism is to find the area of the base (a regular hexagon, meaning that all sides and angles are the same) and multiply by the height of the prism. To find the area of a hexagon you multiply the apothem by the perimeter of the hexagon, and then divide that by 2. the apothem is a line from the center point to the center of any side, forming a right angle with a side, it doesn't matter which one. Once you find the area of the hexagon, multiply it with the height.


What is the formula for calculating the volume of a hexagonal shape?

First we assume it is a regular hexagon meaning all the angles are the same and the sides are the same length. Recalling that a regular hexagon can be broken up into 6 triangles, we find the area of the hexagon by finding the area of one triangle and multiply by six. (recall the area of triangle is Height x 1/2 Base ) You can also find the area of a hexagon using the formula Area==ap/2 where a is the apothem and p is the perimeter. But that just gives you the area of the 2 dimensional base, not the volume. To calculate the volume, multiply the area found above by the height of the hexagonal container.


How do you find the area of a hexagon without a side length?

To find the area of a Regular hexagon with side length (x) you need:1. The "radius" of the hexagon. (Just the length from the center to the outside edge.)2. The apothem. (which is only just half of the height of the base.)**If you don't have one or both of these you can't do it.**Steps:1. Make a triangle of the apothem (used as a) and the radius. (r)2. Use the Pythagorean Theorem to find 1 half of the side length.3. Multiply the actual side length by 6.4. Multiply that by a.5. The area is your answer.


What is the formula for finding the surface area of a hexagon?

Area of triangle = ½ base x altitude. Regular hexagon is 6 equal triangles so Area= 3 x base x altitude


What is the area of a regular octagon with a side length of 4 inches and an apothem length of 4.8 inches?

By joining all the vertices to the centre of the octagon, the apothem forms the height of the triangles with the side of the regular octagon as the base. This the area is 8 × area_triangles = 8 × ½ × side × apothem = 4 × side × apothem: Area_regular_octagon = 4 × side_length × apothem ≈ 4 × 4 in × 4.8 in = 76.8 in²


What is the length of the apothem of a regular hexagon with 10 cm sides?

The hexagon will consist of 6 equilateral triangles of 3 equal sides of 10 cm and the apothem will divide the triangle into 2 right angle triangles with a base of 5 and an hypotenuse of 10 and so by using Pythagoras' theorem the height of the triangle which is the apothem works out as 5 times square root of 3 or about 8.66 cm rounded to 2 decimal places.


How do you find the volume of a pentagonial prism?

Volume is Area of the Base times the Height of the Prism. To find the area of a Regular Pentagon, you use the formula (1/2)*Perimeter*Length of Apothem.


What is area of shaded area if base is 8 and apothem is 5.51?

The answer depends on what part of the figure is shaded!


The area of a regular polygon with apothem a and perimeter P is?

Area = pa/2 Join each vertex to the centre of the n-sided regular polygon. Then the apothem a is the height of each of the isosceles triangles thus created (as each side between a vertex and the centre must be the same length) and their base is the side s of the polygon. Thus the area of the polygon is: Area = n x (sa/2) = nsa/2 But ns = the sum of all the side lengths = perimeter p. Thus: Area = pa/2 Note: for a hexagon, the triangles created are equilateral, but an equilateral triangle is a special case of an isosceles triangle in that the base is also the same length as the other two equal sides.


How do you find the apothem of a hexagon with only the side length?

The apothem is the radial distance from the middle of the side to the centre of the hexagon. A hexagon is six congruent equilateral triangles joined by adjacent sides. Equilateral triangles can be divided into two equal right angled triangles. The upright of the right angled triangle is effectively the apothem of the original hexagon. Pythagoras now kicks in. The apothem (vertical) is A and half the side length (base) is B, the third (longest) side is C and is the same as the original side length. Pythagoras states A2 + B2 = C2. So by transposition, A = root (C2 - B2). As B = 1/2 C, the apothem A is given by: A = root(C2 - (C/2)2) = root(C2 - C2/4) = root(3C2/4) = C x root(3) / 2 So the apothem of a hexagon is 1/2 x root(3) x the side length.