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By joining all the vertices to the centre of the octagon, the apothem forms the height of the triangles with the side of the regular octagon as the base.

This the area is 8 × area_triangles = 8 × ½ × side × apothem = 4 × side × apothem:

Area_regular_octagon = 4 × side_length × apothem ≈ 4 × 4 in × 4.8 in = 76.8 in²

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8y ago
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8y ago

A side of 4 inches does not correspond exactly to an apothem of 4.8 inches.


Side of a regular octagon = 4 inches =>apothem is 4.83 inches, approx
and area = 77.3 sq inches.


Or
Apothem = 4.8 inches =>

side = 3.98 inches, approx

and area = 76.3 sq inches.

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Q: What is the area of a regular octagon with a side length of 4 inches and an apothem length of 4.8 inches?
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Related questions

A regular octagon with sides of length 7 and an apothem of length 8.45 has an area of what?

The area of a regular octagon: A = (2 x apothem)2- (length of side)2 or in this case A= (2 x 8.45)2 - 72


A regular octagon with sides of length 8 and the apothem of length 9.66 has an area of what?

309.12


A regular octagon with sides of length 7 and an apothem of length 10.49 has an area of?

Area in square units = 0.5*(apothem)*(perimeter)


A regular octagon with sides of length 8 and an apothem of length 9.66 has an area of square units?

309.12


A regular octagon with sides of length 11 and an apothem of length 8.85 has an area of square units?

389.40


A regular octagon with sides of length 7 and an apothem of length 10.49 has an area of square units?

293.72


If a regular octagon's apothem is 14.5cm and the length of the side is 12cm what is the area?

i think its 10


A regular octagon with sides of length 8 and an apothem of length 9.66 has an area of how many square units?

By Apothem LengthThe area of a regular octagon can also be computed using its measured apothem (a line from the center to the middle of any side). The formula for an octagon with side length s and apothem a is Area = a4s . (apothem times one-half the perimeter)So for this example, (8 cm and 9.66 cm) Area = (9.66)(32) = 309.12 cm2----By Side LengthThe area of a regular octagon with side length s is given as Area = 4.828427 s2 , so for a regular octagon of side length 8 cm , the area is calculated as 309.02 cm2. (indicating an error from rounding the apothem length)(This formula is generated by adding or subtracting the missing corner triangles.)


What is the area of a regular octagon with a side length of 5.8 centimeters and an apothem length of 7 centimeters?

An octagon with a side length of 5.8 cm has an apothem that is approximately 7 cm. The area of such a shape is approx 162.4 sq cm.


What is the area of a regular octagon with a side length of 5.8 centimeters and a apothem of 7 centimeters?

An octagon with a side length of 5.8 cm has an apothem that is approximately 7 cm. The area of such a shape is approx 162.4 sq cm.


A regular octagon with sides of length 7 and an apothem of length 8.45 has an area of how many square units?

By Apothem LengthThe area of a regular octagon can also be computed using its measured apothem (a line from the center to the middle of any side). The formula for an octagon with side length s and apothem a is Area = a4s (apothem times one-half the perimeter)So for this example, (7 cm and 8.45 cm) Area = (8.45)(28) = 236.6 cm2----By Side LengthThe area of a regular octagon with side length s is given as Area = 4.828427 s2 , so for a regular octagon of side length 7 cm , the area is also about 236.6 cm2.(This formula is generated by adding or subtracting the missing corner triangles.)


A regular octagon with sides of length 11 and an apothem of length 8.85 has an area of what?

An apothem of a regular polygon is a segment from its center to the midpoint of a side. You can use the apothem to find the area of a regular polygon using this formula: A = pa/2 where p is the perimeter of the figure and a is the apothem. For a regular octagon with side length 11, the perimeter p = 8(11) = 88. So the area would be A = 88(8.85)/2 = 389.4 square units.