The GCF is a2b.
The GCF is a2b
It is a2b.
a5+b5 = (a+b) (a4-a3b+a2b2-ab3+b4)
Expand 4ab3 (a2b2-a-1)
351 cid or 5.8L
Because a radical has two solutions, the positive and negative. This means that √(a2b2) has twice as many solutions as ab. ab is in fact a subset of √(a2b2).
What is "a 3b"? Is it a3b? or a+3b? 3ab? I think "a3b" is the following: A is an invertible matrix as is B, we also have that the matrices AB, A2B, A3B and A4B are all invertible, prove A5B is invertible. The problem is the sum of invertible matrices may not be invertible. Consider using the characteristic poly?
a^2b^2(4ab) = 8a^3b^3.
5
5
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