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How can you solve for A in the following expresion c2 equals radical A square plus B square?
I don't think you wanted the word "radical" in your question. Aren't you working with: C2 = A2 + B2 ? Or maybe: C = sqrt ( A2 + B2 ) ? In either case, A = sqrt ( C2 - B2 ). If your question is really the way you typed it, then the answer is more complicated.
The eccentricity of the ellipse if minor axis is equal to the distance between the foci is Answer is 1 radical 2 how?
The standard equation for an ellipse centered at the origin is [x2/a2] + [y2/b2] = 1 We also have the relationship, b2 = a2 - c2 where c is the distance of the foci from the centre and a & b are the half lengths of the major and minor axes respectively. When the length of the minor axis equals the distance between the two foci then 2b = 2c : b = c. Thus, a2 =b2 + c2 = 2b2 One of the formulae for the eccentricity of an ellipse is, e = √[(a2 - b2)/a2] Thus, e = √[(2b2 - b2) / 2b2] = √½ = 1/√2.
How is the expansion of algebraic expressions done?
There are 3 main rules for expansion of algebraic expressions. They are as follows: 1) a2 _ b2 = (a-b) (a+b) 2) (a+b)2 = a2 + 2ab +b2 3) (a-b)2 = a2 - 2ab +b2
What is the sum and difference of two cubes?
a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
How do you solve a to the 3rd power plus b to the 3rd power divided by a plus b?
(a3 + b3)/(a + b) = (a + b)*(a2 - ab + b2)/(a + b) = (a2 - ab + b2)
