Rewrite the equation as y = -(3/4)x - 5
The slope = coefficient of x = -(3/4) = -0.75
-5x-4y = 6 -4y = 5x+6 Divide all terms by -4 y = -1.25x-1.5 Slope = -1.25 and intercept = -1.5
4y - 5 = 7x ∴y = 7/4x + 5/4 slope = 7/4, or 1.75 4y - 5 = 7x ∴4y/7 - 5/7 = x ∴4y/7 - 5/7 = 0 ∴4y = 5 ∴y = 1.2 the y-intercept is 1.2
Point Slope Form - Y=.5X+1.5
23
by just doing the problem
If you mean: 4y = -3x+20 then y = -0.75x+5 whereas -0.75 is the slope and 5 is the y intercept of a straight line equation
11x-4y=32
0.75
x-4y = 5 -4y = -x+5 y = 0.25x-1.25 which is now in slope intercept form
To function form. - 7X - 4Y = 16 - 4Y = 7X + 16 Y = - 7/4X - 4 ------------------------ The slope is, - 7/4 --------
2
2x-4y=4 -4y=-2x+4 y=1/2x-1 Slope is 1/2 (.5)
3x - 4y -16 = 0 Algebraically rearrange to to make '4y' the subject. Hence 4y = 3x - 16 ( Note the change of sign, on taking the '4y' across the equals to replace the zero. ). Divide both sides by ;4; y = (3/4)x - 16/4 y = ( 3/4)x - 4 Hence the slope is ' 3/4 ' and the y-intersect is '-4'. NB For all straight line of the form y = mx + c 'm' is the slope , and 'c' is the y-intersect. All you need to do on being given linear equations of the form px + ny + c = o or px + c = ny or px + ny = c etc. is to algebraically rearrange into the form of y = mx + c , making sure you change the signs correctly, and then dividing both sides by the coefficient of 'y' .
If 8x + 4y = 16, then y = - 2x + 4 Thus the slope is -2 and the intercept is 4.
5x+4y = -3 4y = -5x-3 y = -5/4 x - 3 Slope is -5/4.
It is:- 3x+4y = 8 4y = -3x+8 y = -0.75x+2 So the slope is -0.75 and the y intercept is 2
4y=-5x-12 your slope would be -5/4 your new slope intercept form would be y=-5/4x-3