2(4x + 5)
4x × 4x = (4x)² = 16x²
4x^4 or 4x*4x*4x*4x A formula would be (x^a)(x^b)= x^a+b x^a) / (x^b)= x^a-b
4x - 2x = 2x
4x - 10 = -4x + 22 +4x+10=+4x +10 8x = 32 x = 4
(4x-6)(4x+3)
One way to solve this system of equations is by using matrices. Form an augmented matrix in which the first 2x2 matrix is the coefficient matrix and the 2x1 matrix on its right is the answer. Now apply Gaussian Elimination and back-substitution. Using this method gives x=5 and y=1.
v + 4x - 5
It is 9*(4x + 1).
2(4x + 5)
4x-4=-1
To solve using matrices, you're usually given a set of 2 or more linear equations. Once you have that, isolate the variables and write numerically in the form of a matrix, dividing the right side from the left. Ex. : 2x + 3y = 7; 4x - y = 2 Isolating variables: [2 3 | 7] [4 -1 | 2] From there onwards, it should be easy to solve.
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It is 4x + 4y.
4x + 2 = 54
6x-3y=30 4x=2-y There are many ways to find the values of x and y. elimination substitution matrices on and on... Here's one. Set them both equal to y y=2x-10 y=2-4x So the right sides are both equal to y, therefore, they are equal to each other. 2x-10 = 2-4x 6x=12 x=2 plug 2 in for x on one of the equations y=2-4x y=2-4(2) y=-6
By definition: 4x-10 = 5-x 4x+x = 5+10 5x = 15 x = 3 and y = 2