6x-3y=30
4x=2-y
There are many ways to find the values of x and y.
elimination
substitution
matrices
on and on...
Here's one.
Set them both equal to y
y=2x-10
y=2-4x
So the right sides are both equal to y, therefore, they are equal to each other.
2x-10 = 2-4x
6x=12
x=2
plug 2 in for x on one of the equations
y=2-4x
y=2-4(2)
y=-6
4x+3y = 6 3y = -4x+6 y = -4/3x+2 in slope intercept form
5x+3y
3y - 4x = 24 The first step is to write it in the standard form (y=mx + c) 3y = 4x + 24 y = (4x + 24)/3 y = 4x/3 + 8 The y-intercept is 8 and the slope/gradient is 4/3
To find the extreme value of the parabola y = x2 - 4x + 3 ...(1) Take the derivative of the equation.y = x2 - 4x + 3y' = 2x - 4(2) Set the derivative = 0 and solve for x.y' = 2x - 40 = 2x - 42x = 4x = 4/2x = 2(3) Plug this x value back into the original equation to find the associated y coordinate.x = 2y = x2 - 4x + 3y = (2)2 - 4(2) + 3y = 4 - 8 + 3y = -1So the vertex is at (2, -1).
4x+3y-2x+y 4x-2x+3y+y 2x+4y Taking out 2 common 2(x+2y) Hence the required answer is 2(x+2y)
4x + 3y= 90 -4x -4x _______________ 3y = -4x + 90 /3 /3 ________________ y = -4/3x + 30 hope that helped
-4
5x -6y=-30 5x-6y=30 (2x+3y) (2x-3y)=30 4x+6y=30 4x=30 x=30/4
(4x + 3y)(4x + 3y) or (4x + 3y)2
3y = 4x + 9 -4x + 3y = 9 is the standard form
7
a) 4x+13y=40 b) 4x+3y=-40c) multiply b per(-1)=-4x-3y-40d) sum a and c: 4x+13y-4x-3y=40-(-40)=>10y=80 => y=8to find x replace y per its value in a or b and get x=-16
3y=4x+9.....-4xAnswer: 4x-3y=9
4x+3y = 12 3y = -4x+12 y = -4/3x+4
16x2 + 8x + 1 - 9y2 = (4x + 1)2 - (3y)2 which is a difference of two squares. = (4x + 1 + 3y)*(4x + 1 - 3y)
-4x + 3y = 9
4x+3y = 6 3y = -4x+6 y = -4/3x+2 in slope intercept form