m2-n3=16 :| all i can see to do is guess and plug in. ok, so we know that it has to equal 16... so, lets start with smaller numbers like 8 and 5. note: it is possible for both m and n to be the same number, but in this case, n must be smaller as its a cube. the thing is, i cant find the answer, i went through a lot of choices and I'm already in the hundreds. i don't know if that can be answered... unless.....:| unless m=4, and n=0. :| 42-03=16 :| ..............it was that easy??? sigh. well, there's ur answer.....i went up to 304 for the m for nothing :| im so stupid
(81 - m2) = (9 - m)(9 + m)
9(m-cubed)+(m-squared)
It is: 6*2*2 = 24 square m
m2 - 4mn - 12n2 = m2 - 6mn + 2mn - 12n2 = m(m - 6n) + 2n(m - 6n) = (m + 2n)(m - 6n)
a cube has 6 parallel lines
For variable m and n, the word "square" means m2 and "cube" means m3. The equation becomes m2 - n3 = 16.
(81 - m2) = (9 - m)(9 + m)
Take the cube root of that number. For example, volume is 8 square inches and the cube root of 8 is 2. In case you forgot, if N is the Cube root of a number M then NxNXN=M
13.5 square meters
9(m-cubed)+(m-squared)
Answer: 112 ft² = 10.4051 m²
"m cube" is m3.
It is: 6*2*2 = 24 square m
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
(x-12)2 using perfect square
I'm pretty sure the answer is: C= de3k/ √m (C equals d times e cubed times k, divided by the square root of m).
74 cm^3 = 0.000074 m^3.