I moved your question to the trash. It doesn't make any sense. If you key in your algebra problem correctly, I will help you solve it.
You need to re-write your question with the correct notation. Do you mean this:
(-6y)-(12y)*(7-4y)? The way you wrote it out doesnt make sense.
is it y to the power of 4 or 4y.? doesn't make any sense..
-2x+3y+14 and x+2y+7 1. x+2y+7=0 2. x= -2y-7 3. (substitute new equation in for x) -2(-2y-7)+3y+14=0 4. (distribute) 4y+14+3y+14=0 5. (combine like terms) 7y+28=0 6. (subtract 28) 7y= -28 7. (28 divided by 7 to solve for y) y= -4 8. (substitute -4 value for y) x+2(-4)+7 9. (solve for x value) x-8+7 x-1=0 x=1 10. (answer check) -2(1)+3(-4)+14= 0 (1)+2(-4)+7=0
x+2y-6=z -z -z x+2y-z-6=0 +6 +6 ---------> x+2y-z=6 3y-2z=7 ---------> 0x+3y-2z=7 4+3x=2y-5z -3x -3x ---------> -3x+2y-5z=4 Put them into a matrix, for x,y,z and their answers. Solve for [A]-1[B], and the answer comes to: x= 1.75, y= 1.5, and z= -1.25
9Y + 4 = 2Y + 25 subtract 2Y from both sides 7Y + 4 = 25 subtract 4 from both sides 7Y = 21 divide both sides integers by 7 (7/7)Y = 21/7 Y = 3 -----------------check in original equation 9(3) + 4 = 2(3) + 25 27 + 4 = 6 + 25 31 = 31 ---------------checks
(7x+2)(2y-1)
(1,4) Let (x,y) represent the point of reflection. We know that A and A' must be on the same line as (x,y) and must be equidistant from (x,y). Because they are equidistant from (x,y), we know: (x-3)2+(y-(5))2=(x-(-1))2+(y-(3))2 Now find the line that they are on by using the points A and A': 5=m(3)+b 3=m(-1)+b Subtracting the left and right hand sides of the two equations, gives us: 2=4m -->m=1/2 Using this value of m and substituting into either equation gives us b=7/2. So, all three points are on the line: y=1/2*x+7/2 This is equivalent to x=2y-7. I will substitute this into the first equation to find our point [I could have used y=1/2*x+7/2, but I'm using the value of x to avoid the fractions.] ((2y-7)-3)2+(y-(5))2=((2y-7)-(-1))2+(y-(3))2 (2y-10)2+(y-5)2=(2y-6)2+(y-3)2 4y2-40y+100+y2-10y+25=4y2-24y+36+y2-6y+9 -50y+125=-30y+45 20y=80 y=4 Substituting y=4 into x=2y-7, gives x=1.
10y = 2y - 6y + 7 10y =-4y + 7 10y +4y = 7 14y = 7 y = 1/2 = .5
x = 7 - 2y 3x = 21 - 6y 21 - 6y + 2y = 5 21 - 4y = 5 21 - 16 = 5 4y = 16 y = 4 x + 8 = 7 x = -1 Check it. -3 + 8 = 5 -1 + 8 = 7 It checks.
7x+2y=16 21x+6y=24 y=8-(7/2)x y=4-(7/2)x 0= 4 the system has no rational solution.
x-2y=1 => x=2y+1 (1) 3x+y=-4 (2) sub (1) into (2) 3(2y+1)+y=-4 6y+3+y = -4 7y+3 = -4 7y = -7 y = -1 sub back into (1) x = 2(-1)+1 x = -2+1 x = -1
To solve the equation, we need to combine like terms on both sides. On the left side, 4y + 2y can be simplified to 6y. On the right side, 24 - 1 simplifies to 23. Therefore, the equation can be written as 6y - 7 = 23.
2y2-2y-4 = (2y-4)(y+1) when factored
7
xy(7+2y-3x)-6xy
2x - 3y = -4 3x + 2y = 33 Eqn(1)*2: 4x - 6y = -8 Eqn(2)*3: 9x + 6y = 99 Add the eqns: 13x = 91 so that x = 7 Substitute in eqn1: 14 - 3y = -4 so that 18 = 3y or y = 6 SOLUTION: x = 7, y = 6
6y-1+8=32 y=4 1/6 Here's the steps- 6y-1+8=32 6y+7=32 6y=25 y=4 1/6
Multiply First equation by 2: 6y - 2x = 0Add second equation to this: 6y - 2x + 2x + 2y = 0 + 7Simplify: 8y = 7 so y = 0.875 and x = 2.625
1. x + 2y = 5 3x + 6y = 10 2. x + y + z = 50 2x + 5y = 8z = 4 6x + 7y + 9z = 7 3. x + 2y = 5 1.2x + y = 10