4x + 10 + 3x = 40 - 3x 4x + 10 + 3x + 3x = 40 20x = 40 x = 2
3x+7=37 -7 -7 3x=30 /3 /3 x=10
13-3x = 43 -3x = 43-13 -3x = 30 x = -10
5x - 4 = 3x + 6 5x - 3x = 6 + 4 2x = 10 x = 5
If you factor x2 - 3x - 10, you'll get (x-5) (x+2). If your equation is x2 - 3x -10 = 0, then x = 5, and x = -2.
3x-10 equals 24; add 10 to both sides 3x equals 34; divide by 3 x=11.333 or 11 1/3
3x + 2 = -10 3x = -12 x = -4
(2, -1)
3x - 4y = 10-3x - 4y = 8 -> add line 1 to line 2 3x - 4y = 100x - 8y = 18 -> -8y = 18 -> y = -18/8 = -9/4 -> 3x - 4*(-9/4) = 10 -> 3x + 9 = 10 -> 3x = 1 -> x = 1/3
3x+y=5(4x-7y)=-10 3x+y=20x-35y=-10 -3x -3x y=17x-35y=-10 -y -y 17x-36y=-10 sorry but that's as far as i could get :(
x=10
3x+5= 4x-10+10 +103x+15= 4x-3x -3x15=X
3x+4=10 To solve: 3x+4=10 3x=6 x=2
24
4x + 10 + 3x = 40 - 3x 4x + 10 + 3x + 3x = 40 20x = 40 x = 2
3x+7=37 -7 -7 3x=30 /3 /3 x=10
fx=3x-5 f=(3x-5)/x f2=(6x-10)/x /=divide