x2 - 3X - 10 = (X - 5)(X + 2)So, (X2 - 3X -10) / (X-5) = X + 2
3x=10 x=10/3
If you mean x2-3x+5 then the answer is none because its discriminant is less than zero
1 and 2
x^2+3x-18=0 (x+6)(x-3)=0
-2
x2 + 3x - 10 = (x + 5)(x - 2) ⇒ x = -5 or 2
x2 - 3x + 2 = 0
x = -5 x = 2
x2 - 3X - 10 = (X - 5)(X + 2)So, (X2 - 3X -10) / (X-5) = X + 2
do you mean x2 + 3x + 2 ? Factors are (x +2)(x+1)
x2-3x-10 = (x+2)(x-5) when factored
x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
x2+3x-10 = (x+5)(x-2) when factored
x = 2
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.