7(5x + 9y)
1. 6x - 5y = 22 2. 5x - 9y = -1 1 times 5: 30x - 25y = 110 2 times 6: 30x - 54y = -6 Subtract : 29y = 116, so y = 4 and x therefore = 7
5x + 9y = 06x + 6y = 2 use substitution method5x + 9y = 0y = -5x/96x + 6y = 2 substitute y with -5x/96x + 6(-5x/9) = 26x - 30x/9 = 2 multiply by 9 to both sides54x - 30x = 1824x = 18x = 24/18 = 4/3y = -5x/9 = (-5/9)x substitute x with 4/3y = (-5/9)(4/3) = -20/27Thus the solution is x = 4/3 and y = -20/27.
-5x + y = -12- 3x + 6y = -12Since both of expressions have a value of -12, their sum is - 24. This is true only whenx = 20/9 and y = -8/9.-5x + y = -12y = 5x - 12- 3x + 6y = -12-3x + 6(5x - 12) = -12-3x + 30x - 72 = -1227x = 60x = 60/27x = 20/9y = 5x - 12y = 5(20/9) - 12y = 100/9 - 12y = (100 - 108)/9y = -8/9
(x+5)(x+5)
The variables have no known values and as an expression it is: 5x+9y+5
13x - 9y - 10
Slope-intercept form is y = mx + b5x + 9y = -36Subtract 5x from each side:9y = -5x - 36Divide everything by 9:y = -5/9x - 4
It is 12x + 11y + 9.
5x-4y+9y+x-9+7 = 5x + x - 4y + 9y - 9 + 7 = 6x + 5y - 2 ■
I x=5 and y=2, then (5x5)=25 plus (9x2)=18. 25+18=43
If: 5x-9y = 7 and 7y-3x = -5 Then: x = 1/2 or 0.5 and y = -1/2 or -0.5
Y-8x plus 9y equals 10y-8x.
7(5x + 9y)
1. 6x - 5y = 22 2. 5x - 9y = -1 1 times 5: 30x - 25y = 110 2 times 6: 30x - 54y = -6 Subtract : 29y = 116, so y = 4 and x therefore = 7
5x + 9y = 06x + 6y = 2 use substitution method5x + 9y = 0y = -5x/96x + 6y = 2 substitute y with -5x/96x + 6(-5x/9) = 26x - 30x/9 = 2 multiply by 9 to both sides54x - 30x = 1824x = 18x = 24/18 = 4/3y = -5x/9 = (-5/9)x substitute x with 4/3y = (-5/9)(4/3) = -20/27Thus the solution is x = 4/3 and y = -20/27.
YES : Equation (1) 5x - y = 3x + 9y = 19 : Multiply by 5 →Equation (2) 5x + 45y = 95Subtract Equation (1) from Equation (2) to eliminate 'x' terms. This gives : 45y -(-y) = 95 - 3 : 46y = 92 : y = 2Substituting for y in Equation(1) gives : 5x - 2 = 3 : 5x = 3 + 2 = 5 : x = 1Substituting for x and y in the equation 3x + 4y - 6c = -7 gives : 3 + 8 - 6c = -7 : 6c = 11 + 7 = 18 : c = 3