7x + 16 = 3x + 4 4x = -12 x = -3
(7x + 4) = (3x + 7) Subtract (3x + 4) from both sides of the equation. (7x + 4) - 3x - 4 = (3x + 7) - 3x - 4 4x = 3 x = 3/4 Check: (7x + 4) = 7 (3/4) + 4 = (21/4) + 4 = (21/4) + (16/4) = 37/4 (3x + 7) = 3 (3/4) + 7 = (9/4) + 7 = (9/4) + (28/4) = 37/4 Yay.
7x - 8a = 3x + 24a First, add 8a to both sides: 7x = 3x + 24a + 8a Now subtract 3x from both sides to get all x terms on one side: 7x - 3x = 24a + 8a Simplify... 4x = 32a And divide both sides by 4: x = 32a / 4 = 8a x = 8a
The given equation is not that of a parabola.
3(x+4) is the same as 3x+12 when the brackets are expanded out
combine like terms. 3x+1+4x-5=31 3x+4x=7x 7x+1-5=31 1-5=-4 7x-4=31 then solve it 7x=35 x=5
7x + 16 = 3x + 4 4x = -12 x = -3
7x+2 = 3x-2 7x-3x = -2-2 4x = -4 x = -1
3x2-7x+4 = (3x-4)(x-1) when factored
(3x - 4)(x - 1)
3x/4 + x = 7x/4 because 4x/4 = x 3x/4 + 4x/4 = 7x/4
7x-4 = 3x+36Add 4, it cancels out.. So,7x = 3x+40Now subtract 3x from 7x..4x = 40..40 divided by 4 is 10So, X= 10
The sum of the coefficients is 3 - 7 + 4 = 0 so (x - 1) is a factor. Thus, 3x2 - 7x + 4 = 3x2 - 3x - 4x + 4 = 3x(x - 1) - 4(x - 1) = (3x - 4)(x - 1)
72-4*3*4 = 1
7x - 9 = 3x + 5 7x - 3x - 9 = 5 7x - 3x = 5 + 9 4x = 14 x = 14/4
3x - 2y + 7x + 4y = 3x + 7x - 2y +4y = (3+7)x + (-2+4)y = 10x + 2y
7x-3=3x+8 7x-3x=8+3 4x=11 x=11/4=2.75