The sum of the coefficients is 3 - 7 + 4 = 0 so (x - 1) is a factor.
Thus,
3x2 - 7x + 4 = 3x2 - 3x - 4x + 4 = 3x(x - 1) - 4(x - 1) = (3x - 4)(x - 1)
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The factors are -1(2x + 1)(3x + 4)
6x2 + 5x - 6 is factored out to (2x + 3)(3x - 2).
In one bracket, write 16 times the square root of 2 minus 3x. In the other one, write 16 times the square root of 2 plus 3x.
3(x2 + 3x + 1)
(x - 4)(3x - 2)