Get your book open and work out the problem. You need to do this.
Yes it is. There is no fraction which, when cubed, equates to 5. Consider n = p/q where p and q are integers expressed in lowest terms (they are relatively prime). If n3 = 5, then p3 / q3 = 5. This equates to an integer if and only if q3 = 1 meaning q = 1 or if p3 is divisible by q3. The latter is impossible since p and q are relatively prime. Thus, for n to be the cube root of 5 and be rational, it must be an integer. No integer cubes to 5 (1, 8, ...). Thus, the cube root of 5 is irrational.
Q(t) = Q0(1.14t) Q = the quantity at time t t = time (in, say, years) Q0 = the quantity at time zero For example, if t = 5 years and Q0 =1000, Q(5) = 1000(1.145) = 1000x(1.925414...) = 1925.414... = about 1925.
Write an algebraic expression for the verbal expression. q squared minus 2 times q
This problem can be solved by solving the system of equation. Total worth of coins: $2.65 Total number of coins: 33 n= number of nickels q= number of quarters since we know that there are 33 coins total, we can set the equation like this: number of nickels + number of quarters = total number of coins => n+q=33 We also know that the worth of these coins is $2.65. each nickel is worth of $0.05 each quarter is worth of $0.25 therefore we can set the equation: 0.05 x number of nickels + 0.25 x number of quarters = total worth of coins. 0.05n+0.25q=2.65 However, for convienience, we should multiply the equation above by 100 to get rid of decimals. Thus it is 5n+25q=265 you will now have a following set of 2 equations: n+q=33 5n+25q=265 Use the SUBSTITUTION METHOD to solve either n or q for solving n: (replace q with n if you're willing to solve q instead) n+q=33 => n=33-q (since n is equal to 33-q, we can -q -q substitue n in the other equation.) 5(33-q)+25q=265 => 165-5q+25q=265 => 20q=100 => q=5 -165 -165 /20 /20 There are 5 quareters as a result.(or 28 nickels) since you know that q=5 you can substitute q in the first equation. n+(5)=33 => n=28 - 5 -5 therefore, there are 5 quarters and 28 nickels. ELIMINATION METHOD: n x -5 + q x -5 = 33 x -5 => -5n-5q=-165 5n+25q=265 + 5n+25q=265 ------------- 20q=100 => q=5 /20 /20 Or simply we can say: if we have x quarters, we have .25x value of them. So the value of nickels will be 2.65 - .25x. Since we have 33 coins, and x quarters, then the number of nickels will be 33 - x. So the value of all nickels would be also .05(33 - x). Thus, we have:2.65 - .25x = .05(33 - x)2.65 - .25x = 1.65 - .05x2.65 - 1.65 - .25x + .25x = 1.65 - 1.65 - .05x + .25x1 = .20x1/.20 = .20x/.20x = 5 the number of quarters 33 - x= 33 - 5= 28 the number of nickels. Thus, we have 5 quarters and 28 nickels.
22.6
Q equals 100 Q/5=20 Multiply by 5 on each side 5(Q/5)=20 Q=100
Q(p+5) or q(p)+5
(q + 6) (q + 5) = q2 + 11q + 30
the sum of q plus 5!
2(q^2 - 5) or 2(q - the square root of 5)(q + the square root of 5)
Q(5n)
three-fourths of the sum of q and 5
Q Hasan is 5' 7".
155
State the problem: 35q = 5 Solve for q by dividing both sides by 35 (to isolate the q variable): q = 5 ÷ 35 or 5/35, simplified to 1/7, or 0.142857 in decimal form.
The answer to the equation -q = -5 is indeed q = 5. When we have a negative sign on both sides of the equation, they cancel each other out, resulting in q = 5. As for the expression 8-q+4 = -q+4⋅46, it seems to be an unrelated equation. Without a clear question or instructions, it's not possible to determine what you are asking for. If you provide more context or specific instructions, I'll be happy to assist you further.
The cast of Q Pootle 5 - 2013 includes: Ed Gaughan as Q Pootle 5 Ella Kenion as Stella Joanna Page as Oopsy