When factored it is: (x-9)(x+4)
Assuming that x2 is x squared: (x - 9)(x + 4)
. x + 4
(x - 2)(x - 3)
x2-5x+4 = (x-1)(x-4) when factord
When factored it is: (x-9)(x+4)
x2-5x-36 = (x-9(x+4) when factored
the question is to solve (x^2-5x+5)^(x^2-36)=1
Assuming that x2 is x squared: (x - 9)(x + 4)
I assume x2 + 5x - 36 is the polynomial in the question. First, look for two factors of 36 that have a difference of 5, which would be 9 and 4. It would factor into (x + 9)(x - 4). To double check, multiplying them together results in x2 - 4x + 9x - 36 = x2 + 5x - 36. If the polynomial is 5x2 +7x +2
. x + 4
1st = x2nd = 5 - xx(5 - x) = -365x - x2 = -365x - x2 + 36 = -36 + 365x - x2 + 36 = 0-1(- x2 + 5x + 36 = 0)x2 - 5x - 36 = 0(x + 4)(x - 9) = 0(x + 4) = 0 or (x - 9) = 0x = -4 or x = 9Thus, the integers are -4 and 9
It is (x - 9)*(x + 4)
x - 4. x^2 + 5x - 36 = (x - 4) (x + 9) x^2 - 9x + 20 = (x - 4) (x - 5)
x2-5x-36 = (x-9)(x+4) when factored
x2 + 5x - 120 can not be factored.
(3x - 5x) + (x2 - 6x2) = -2x -5x2 = -x(2 + 5x)