x2-5x-36 = (x-9)(x+4) when factored
(5x - 6)(5x + 6)
9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)
964 = 1,000 - 36
(5y - 6)(5y + 6)
(x^2 - 4)(x^2 + 9) set to zero to see roots ( watch out for the surprise! )
4(y - 3)(y + 3)
(x + 6)(x - 6)
(5x - 6)(5x + 6)
(x + 12)(x - 3)
(6x - 1)(6x - 1)
49x2 - 84x + 36 = (7x - 6)(7x - 6) or (7x - 6)2
2x^(2) + 72 Factors to 2( x^(2) + 36) s(x^(2) + 6^(2)) Does NOT factor. NB Remember . two squared terms with a positive(+) between them does NOT factor!!!! However, two squared terms with a negative(-) between DOES factor . e.g. x^(2) + 6^(2) Does NOT factor x^(2) - 6^(2) factors to ( x - 6)( x + 6 ) Note the different signs. Similarly 8^(2) + 6^(2) does NOT factor 8^(2) - 6^(2) factors to (8 - 6)(8 + 6) Or using the ~Pythagorean Equation. h^(2) = a^(2) + b^(2) Does NOT factors However, a^(2) = h^(2) - b^(2) factors to a^(2) = (h - b)(h + b) .
9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)
x 2 - 5x - 36 = 0; factor. (x-9)(x+4) = 0; set each factor = 0. x - 9 = 0 and x + 4 = 0 So, x = 9 and x = -4.
964 = 1,000 - 36
x^(2) - 36 = x^(2) - 6^(2) Remember two squared terms , as above, with a NEGATIVE between them can factor to (x - 6)(x + 6) NB #1 ; The different signs in the brackets. #2, Two squared terms with a POSITIVE (+) between them, does NOT factor. #3 ; Inspect the constant, to see if it is a squared number ; 36 = 6^(2) in this case.
(5y - 6)(5y + 6)