Not enough information.The antilog of 1182 is 10 to the power 1182, or e to the power 1182, or some other number to the power 1182 - whatever you choose to use as your basis for logarithms.
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Assuming base-10 logarithms the antilog of 2.068 is 116.95 (to two decimal places).
The value of antilog(1.0913) depends on the base to which the logarithm was taken. Antilog(1.0913) = Base1.0913. The two most common bases are e = 2.71828 (approx) and 10. If the base was e, then antilog(1.0913) = e1.0913 = 2.978 If the base was 10, then antilog(1.0913)= 101.0913 = 12.340
Assuming working to base '10' , then Antilog 2.3909 is 10^(2.3909) = 245.9801149/ Remember for logarithms. log of a number is log(10)[number] Hence its antilog is 10^(log number).
The antilog of a number is the inverse operation of taking the logarithm of that number. In this case, the antilog of 0.176 can be found by raising 10 to the power of 0.176. This is equivalent to 10^0.176, which is approximately equal to 1.495. So, the antilog of 0.176 is approximately 1.495.
Antilog ((log 45)/3)