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Assuming base-10 logarithms the antilog of 2.068 is 116.95 (to two decimal places).
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How do you find the anti log of 1.0913?
The value of antilog(1.0913) depends on the base to which the logarithm was taken. Antilog(1.0913) = Base1.0913. The two most common bases are e = 2.71828 (approx) and 10. If the base was e, then antilog(1.0913) = e1.0913 = 2.978 If the base was 10, then antilog(1.0913)= 101.0913 = 12.340
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Assuming working to base '10' , then Antilog 2.3909 is 10^(2.3909) = 245.9801149/ Remember for logarithms. log of a number is log(10)[number] Hence its antilog is 10^(log number).
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Raise 10 to the power of the number. The antilog of 2 is 102 = 100 The antilog of 5 is 105 = 10,000 The antilog of 'pi' is 103.1416 = 1,385.46 (rounded)
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