Best Answer

hey....

Q: What is the approximate minimum stream velocity needed to keep a 6.4-cm-diameter particle in motion?

Write your answer...

Submit

Still have questions?

Continue Learning about Algebra

A parabola's maximum or minimum is its vertex.

It means the minimum current can trigger the SCR to operate.

A parabola has a minimum value when it looks like the letter U

By taking the derivative of the function. At the maximum or minimum of a function, the derivative is zero, or doesn't exist. And end-point of the domain where the function is defined may also be a maximum or minimum.

One period of a sinusoid with no constant component has 1 maximum, 1 minimum,and 1 zero crossing, and 2 zero end-points.Total = 5 points.

Related questions

4)200cm/s

10 centimeters/second

gases

No.Orbital Velocity is the velocity required by a body to achieve a circular orbit around its primary.Escape velocity is the minimum velocity needed to escape a gravitational field

Escape velocity is what a moving body has to achieve in order not to be pulled back down to the planet. For Earth it is about 7 miles per second.

Energy = Mass * Velocity squared. It all depends on the mass and the velocity. The MINIMUM velocity of a meteoric impact is about 7 miles per second, the speed at which an item would fall from free space. Things coming in from the outer solar system could be going several times faster, and a particle falling from deep space could be going upwards of 50 miles per second.

About 1000 meters

As velocity never exceeds the velocity of light.... so i hope a man running with the velocity of light will not be able to throw a ball with any velocity.......... we may get the maximum n minimum velocity with which that can be thrown mathematically that we may get it to be zero................

0 m/s (no motion)

if it was a continuous velocity then 10mps i guess because that is the terminal velocity when an object is dropped this is another person who answer actuallyn you are wrong terminal velocity is the maximum

The PI and the RI were calculated as:PI=(PSV-MDV)/MVandRI=(PSV-MDV)/PSVwhere PSV=peak systolic velocity, MDV=minimum diastolic velocity, and MV=mean velocity (time averaged velocity).

Minimum speed occurs at the top, which is the same as the horizontal component of velocity anywhere along the path.