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What else can I help you with?
How do you find the range and domain of a graph function?
Assuming the standard x and y axes, the range is the maximum value of y minus minimum value of y; and the domain is the maximum value of x minus minimum value of x.
What name is given to the turning point also known as the maximum or minimum of the graph of a quadratic function?
vertex
What do you call the maximum or the minimum of a parabola?
A parabola's maximum or minimum is its vertex.
How do you tell if a quadratic function is minimum value or a maximum vale?
Standard notation for a quadratic function: y= ax2 + bx + c which forms a parabola, a is positive , minimum value (parabola opens upwards on an x-y graph) a is negative, maximum value (parabola opens downward) See related link.
When a feasible region is bounded on all sides where will the maximum and minimum values of the objective function occur?
Surely, you should check the value of the function at the boundaries of the region first. Rest depends on what the function is.
How do you determine the range of a function?
Find the maximum and minimum values that the function can take over all the values in the domain for the input. The range is the maximum minus the minimum.
What is maximum or minimum of function?
Addition is the maximum or minimum function in math.
How can you use the zeros of a function to find the maximum or minimum value of the function?
You cannot. The function f(x) = x2 + 1 has no real zeros. But it does have a minimum.
How do you find minimum and maximum value of calculus?
For the function y = x^(3) + 6x^(2) + 9x Then dy/dx = 3x^(2) + 12x + 9 At max/min dy/dx = 0 Hence 3x^(2) + 12x + 9 = 0 3(x^(2) + 4x + 3) = 0 Factor (x + 1)(x + 3) = 0 Hence x = -1 & x = -3 are the turning point (max/min) To determine if x = 0 at a max/min , the differentiate a second time Hence d2y/dx2 = 6x + 12 = 0 Are the max/min turning points. Substitute , when x = -1 6(-1) + 12 = (+)6 minimum turning point . x = -3 6(-3) + 12 = -6 maximum turning point. When x = positive(+), then the curve is at a minimum. When x = negative (-), then the curve is at a maximum turning point. NB When d2y/dx2 = 0 is the 'point of inflexion' , where the curve goes from becoming steeper/shallower to shallower/steeper. So when d2y/dx2 = 6x + 12 = 0 Then 6x = -12 x = -2 is the point of inflexion. NNB When differentiating the differential answer gives the steeper of the gradient. So if you make the gradient zero ( dy/dx = 0) , there is no steepness, it is a flat horizontal line
What is the maximum and minimum of quadratic function parent function?
The minimum is the vertex which in this case is 0,0 or the origin. There isn't a maximum.....
How do you find maximum or minimum of a function?
y=2x2-3x2-12x+5=0
How do you find the minimum and maximum points of a function?
Set the first derivative of the function equal to zero, and solve for the variable.
How do you get minimum or maximum value of constant in a function?
To find the minimum or maximum value of a constant in a function, you first need to identify if the constant is part of a larger expression or if it stands alone. If it's part of a function, you can analyze the function's critical points by taking its derivative and setting it to zero to find local extrema. Then, evaluate the function at these critical points and the boundaries of the domain to determine the overall minimum or maximum value. If the constant is standalone, it remains unchanged as it does not vary with input.
How do you get a maximum displacement?
To determine the maximum displacement, you need to calculate the peak value of the displacement function. This is done by finding the extreme values (maximum or minimum) of the function, typically by taking the derivative and setting it to zero to find critical points. Once you have these critical points, evaluate the function at those points to find the maximum displacement.
How can you find the extremums in a function?
The general procedure is to find the function's derivative, and then solve for (derivative of the function) = 0. Each of these solutions may be a local maximum or minimum - or none. Further analysis is required. A local maximum or minimum may also occur at points where the derivative is undefined, as well as at the function's endpoints (assuming it is only defined for a certain range, for example, from 0 to 10).
How do you find the range and domain of a graph function?
Assuming the standard x and y axes, the range is the maximum value of y minus minimum value of y; and the domain is the maximum value of x minus minimum value of x.
How do you determine wheather a quadratic function has a maximum or minimum and how do you find it?
In theory you can go down the differentiation route but because it is a quadratic, there is a simpler solution. The general form of a quadratic equation is y = ax2 + bx + c If a > 0 then the quadratic has a minimum If a < 0 then the quadratic has a maximum [and if a = 0 it is not a quadratic!] The maximum or minimum is attained when x = -b/2a and you evaluate y = ax2 + bx + c at this value of x to find the maximum or minimum value of the quadratic.
