Area = 289 sq cm so length of side = sqrt(289) = 17 cm Then perimeter = 4*side = 4*17 = 68 cm
6 cm * 10 cm
Well if what you are asking is whether you would use perimeter or area to measure a set amount of wallpaper the answer is area; e.g. 1 sq. ft. of wall paper
Any positive value upto 36 square units. A 6x6 square will have the maximum area of 36 sq units; a 5x7 rectangle will have an area of 35 sq units, and the area will be reduced as you reduce one of the measures and increase the other so that their sum remains 12 units so that the perimeter is 24 units. 1x11 will be 11 sq units 0.1x11.9 will be 1.19 sq units 0.01x11.99 will be 0.1199 sq units 0.001x11.999 will be 0.011999 sq units, etc.
14 cm
9 sq cm
Perimeter = 104 cmArea = 676 sq cm.
A 4 ft by 9 ft rectangle
120 sq cm
36 cm2 Area of a rectangle is length times width, so you would multipy 12cm by 3 cm to get 36 sq. (squared) cm.
60 sq cm
The perimeter is 10 + 3 + 10 + 3 = 26 in. The area is indeterminate because a quadrilateral is not a rigid shape and can be "squished". The area is anything between 0 and 30 sq inches.
12cm x 12cm originally (144 sq cm area)
30 sq cm ((12 x 5)/2)
If the perimeter is 32 sq cm, there is a very serious problem since the perimeter is a linear measure, not an area! Leaving that aside, the length of the rectangle is 10 cm and the breadth is 6 cm.
The perimeter of a square with an area of 25 sq ft is 20 feet because each side of the square is 5 feet, so the perimeter must be 4 x 5 feet.
* It is unclear if the question is asking about two rectangles, each with a perimeter of 16, or two rectangles whose perimeters sum to 16. This answer assumes the former.Other than the 4x4 square, which coincidentally has both a perimeter and area of 16, some examples would be:1 x 7 rectangle : perimeter 16 in. , area 7 sq. in2 x 6 rectangle : perimeter 16 in., area 12 sq. in3 x 5 rectangle: perimeter 16 in., area 15 sq. inYou can calculate that for a given perimeter, the largest area is found in the square with a side measurement of P/4, i.e. the length and the width are the same.