A 4 ft by 9 ft rectangle
36 ft
They are: 3 ft by 15 ft
Perimeter of the square: 4*9 = 36 feet
No. Take a square with each side 9 feet long. The perimeter is 9+9+9+9 = 36 ft and the area is 9 x 9 = 81 square feet. Now squash the square down a bit so that it is a 7 x 11 rectangle. The perimeter is still 36 ft, but the area is now smaller at 77 square feet. Squash it right down to just 1 ft tall by 17 ft wide and the perimeter is still 36 ft, but the area is now just 17 square feet. So for any given perimeter, the closer the shape of a rectangle is to a square, the larger will be the area.
The area is not sufficient information to determine the perimeter. First of all, there is no reason to suppose that the area is rectangular as opposed to circular or triangular or some other simple or complicated shape. So, all that can be said is that the perimeter is greater than 178.97 feet, a perimeter that is attained when the area is a circle. If the area is a rectangle, it could be 25.49 ft * 100 ft so that the perimeter is approx 250.98 ft or 2.549 ft * 1000 ft and a perimeter of 2005.10 ft or 0.2549 ft * 10000 ft and a perimeter of 2000.51 ft or 0.0002549 ft * 10000000 ft and a perimeter of 2000000 ft. By making the rectangle thinner and longer, the perimeter can be increased without limit.
36 ft
They are: 3 ft by 15 ft
Perimeter of the square: 4*9 = 36 feet
81 square feet.
No. Take a square with each side 9 feet long. The perimeter is 9+9+9+9 = 36 ft and the area is 9 x 9 = 81 square feet. Now squash the square down a bit so that it is a 7 x 11 rectangle. The perimeter is still 36 ft, but the area is now smaller at 77 square feet. Squash it right down to just 1 ft tall by 17 ft wide and the perimeter is still 36 ft, but the area is now just 17 square feet. So for any given perimeter, the closer the shape of a rectangle is to a square, the larger will be the area.
Perimeter of [ 16 x 26 ] rectangle = 16 + 16 + 26 + 26 = 84-ft . Perimeter of a 20-ft square = 4 x 20 = 80-ft . The rectangle has the greater perimeter.
perimeter 182 ft. area 1960 square ft.
The area is not sufficient information to determine the perimeter. First of all, there is no reason to suppose that the area is rectangular as opposed to circular or triangular or some other simple or complicated shape. So, all that can be said is that the perimeter is greater than 178.97 feet, a perimeter that is attained when the area is a circle. If the area is a rectangle, it could be 25.49 ft * 100 ft so that the perimeter is approx 250.98 ft or 2.549 ft * 1000 ft and a perimeter of 2005.10 ft or 0.2549 ft * 10000 ft and a perimeter of 2000.51 ft or 0.0002549 ft * 10000000 ft and a perimeter of 2000000 ft. By making the rectangle thinner and longer, the perimeter can be increased without limit.
Not at all.Rectangle A:-- Length = 20-ft, Width = 10-ft.-- Area = 200 square ft-- Perimeter = 60-ftRectangle B:-- Length = 16-ft, Width = 12.5-ft-- Area = 200 square ft-- Perimeter = 57-ftRectangle C:-- Length = 40-ft, Width = 5-ft-- Area = 200 square ft-- Perimeter = 90-ftRectangle D:-- Length = 50-ft, Width = 4-ft-- Area = 200 square ft-- Perimeter = 108-ftRectangle E:-- Length = 100-ft, Width = 2-ft-- Area = 200 square ft-- Perimeter = 204-ftRectangle F:-- Length = 800-ft, Width = 3 inches-- Area = 200 square ft-- Perimeter = 1600-ft 6-in
The smallest possible perimeter is 20-ft, but there is no largest possible perimeter.You can make it as large as you want, with no limit.Examples:5-ft x 5-ft . . . . area = 25 ft2 . . . perimeter = 20 ft2.5-ft x 10-ft . . area = 25 ft2 . . . perimeter = 25 ft1-ft x 25-ft . . . area = 25 ft2 . . . Perimeter = 52 ft6-in x 50-ft . . . area = 25 ft2 . . . Perimeter = 101 ft3-in x 100-ft . . area = 25 ft2 . . . perimeter = 2001/2 ft1-in x 300-ft . . area = 25 ft2 . . . perimeter = 6001/6 ft0.1-in x 3,000-ft . . area = 25 ft2 . . . perimeter = 6,0001/60 ft
Perimeter = 2*(Length + Width) So 36 = 2*(L+4) => 18=L+4 => L = 14 ft So area = Length * Width = 14*4 = 56 sq ft
A rectangle measuring (200-ft x 240-ft) has Area = 48,000 square ft Perimeter = 880 ft