Too many dimensions have been given to work out an area which normally has only 2 dimensions.
Area, A, is two dimensional so has a width and length, say. You have three dimensions. A three-dimensional entity has a width, length, and height, represented by V (for volume). The size of your volume entity is 5 x 4 x 8 inches = 160 cubic inches.
That depends on what unit...For Examplein miles 3.959 x 10^3in yards 6.967840 X 10^6in feet 2.0903520 x 10^7in inches 2.50842240 x 10^8in megameters 6.371 x 10^1in kilometers 6.371 x 10^3in hectometers 6.371 x 10^4in meters 6.371 x 10^6in centimeters 6.371 x 10^8in millimeters 6.371 x 10^9in cubits 1.3935680 x 10^7
4in,6in,8in,10in,12in,20,and sheet20x30 us style pizzas only
there are different sizes for different ages the smallest is 8in then 10in then 12in the girls in 12u and up play with the 12in
560
12in = 1ft Therefore 8in + 4in = 12in = 1ft 1ft + 8ft + 2ft = 11ft
he has an 8in,10in,12in,13in,2 15inches,16in,and 18in
136 in.
the answer is 31in. unit
6ft 4in minus 3ft 8in
160 cubic inches
4 inches and 5inches
No but nearly
Too many dimensions have been given to work out an area which normally has only 2 dimensions.