Area, A, is two dimensional so has a width and length, say. You have three dimensions. A three-dimensional entity has a width, length, and height, represented by V (for volume).
The size of your volume entity is 5 x 4 x 8 inches = 160 cubic inches.
Too many dimensions have been given to work out an area which normally has only 2 dimensions.
It depends on the shape of the area. Four sides of a quadrilateral - if that is what the given measurements are - do not determine a unique shape.
Area of 4 in x 6 in is 24 in^2.
area of triangle: area equals base times height devided by two! a=bxh/2 a=40in b=20in THE ANSWER IS 4in as the height!
10pi
136 in.
338
6ft 4in minus 3ft 8in
what is the volume of the rectacgular solid 2in,5in,3in.
Too many dimensions have been given to work out an area which normally has only 2 dimensions.
2 ft 6 in
4+4+6+5 = 19 inches is the perimeter
fish about 5in or 4in lowest
19 in
no: if you have two triangles with the same angle measurements, but one has side lengths of 3in, 4in, and 5in and the other has side lengths of 6in, 8in, and 10in, then they are similar. Congruent triangles have the same angle measures AND side lengths.
It depends on the shape of the area. Four sides of a quadrilateral - if that is what the given measurements are - do not determine a unique shape.
The area of a rectangle = length x width = 5 x 8 = 40 square inches.