Area, A, is two dimensional so has a width and length, say. You have three dimensions. A three-dimensional entity has a width, length, and height, represented by V (for volume).
The size of your volume entity is 5 x 4 x 8 inches = 160 cubic inches.
It depends on the shape of the area. Four sides of a quadrilateral - if that is what the given measurements are - do not determine a unique shape.
Area of 4 in x 6 in is 24 in^2.
Alright, darling, let's break it down. First, add up the dimensions: 5.3 + 8 + 4 + 8 = 25.3 inches. Then, divide that sum by 2: 25.3 / 2 = 12.65 square inches. So, the area of the figure is 12.65 square inches. Hope that clears things up for ya, sugar!
10pi
area of triangle: area equals base times height devided by two! a=bxh/2 a=40in b=20in THE ANSWER IS 4in as the height!
136 in.
338
6ft 4in minus 3ft 8in
what is the volume of the rectacgular solid 2in,5in,3in.
2 ft 6 in
4+4+6+5 = 19 inches is the perimeter
fish about 5in or 4in lowest
19 in
It depends on the shape of the area. Four sides of a quadrilateral - if that is what the given measurements are - do not determine a unique shape.
no: if you have two triangles with the same angle measurements, but one has side lengths of 3in, 4in, and 5in and the other has side lengths of 6in, 8in, and 10in, then they are similar. Congruent triangles have the same angle measures AND side lengths.
The area of a rectangle = length x width = 5 x 8 = 40 square inches.
The dimensions given fit that of a right angle triangle