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You can't tell. The perimeter doesn't tell you the area. There are an infinite
number of different rectangles, with different dimensions and different areas,
that all have perimeters of 56.
The greatest area it can have is 196 cm2 ... if it's a square with 14-cm sides.
If it's not a square, then it can have any area less than 196 cm2.
Here are a few rectangles. They all have perimeters of 56:
1 x 27, area = 27
2 x 26, area = 52
3 x 25, area = 75
4 x 24, area = 96
5 x 23, area = 115
10 x 18, area = 180
13 x 15, area = 195
What else can I help you with?
What are the dimensions of a rectangle that has a perimeter of 56 units and 96 square units?
What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units
What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units?
4 x 24
The area of a rectangle is 56 square inches The width of the rectangle is 7 in What is the length?
Area = LxW Using the figures you have 56 = L x 7 L = 56/7 L = 8
The length of a rectangle is three times its width If the area of the rectangle is 147 what is its perimeter?
Write a a series of equations as follows p=2l+2w (formula for perimeter) a=l*w (Formula for area) l=3w (fact given in the question) a=147 (fact given in hte question) We don't currently have enough information to solve the perimeter formula for this rectangle, so we begin with the area formula to get more information. By substituteing 147 for the variable a and 3w for the variable l, we arrive at this equation: 147=w*3w With only one variable, we can solve this equation by isolating w on one side as follows 147=3w2(Multiply w by w to combine like terms) 147/3=3w2/3 (divide both sides by 3) 49=w2 sqrt49=sqrtw2(square root of both sides) 7=w We now know that the width of the rectangle is 7. We also know that the length is three times that, which is 21. We can substitute these values into the perimeter eequation as follows: p=(2*7)+(2*21) p=14+42 p=56 The perimeter of the rectangle is 56
The perimeter of a rectangular garden is 302 feet If the width of the garden is 56 feet what is its length?
Take perimeter of the garden is 302 feet. The width is 56 feet on both sides. Take 56 * 2 because a rectangle has 4 sides, two being the width. 56 *2 = 112. Take 112 from 302 (302-112) = 190. Take 190 and divide by two to get your length. (190/2) = 95. 95 is its length on one side. Length = 95. Width = 56. 56+56+95+95 = 302. Answer by Mathew Cutshall.
What is the area of a rectangle that measures 7 centimeters by 8 centimeters?
The area for a 7cm by 8cm is 56.
What are the dimensions of a rectangle that has a perimeter of 56 units and 96 square units?
What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units
What are he dimensions of a rectangle has perimeter of 56 units and an area of 96 squae units?
4X24
What is the area of an 7 by 8 rectangle?
Area=7x8=56 Perimeter would be (2x7) + (2x8) = 30
If a rectangle has a perimeter of thirty six feet and its four feet wide what is the area?
56 square feet 56 square feet
What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units?
4 x 24
What is the perimeter of a rectangle whose length is 18 cm and breadth is 10 cm?
56 cm Perimeter of a rectangle is given by 2(length + breadth). So, perimeter of given rectangle = 2(18 + 10) = 56
What is the perimeter of this rectangle 18ft by 10ft?
56 feet.
What is the perimeter of 16 and 12 of the shape of a rectangle?
56
What is the perimeter of a rectangle with 21 x 7?
56
What is the perimeter and the area of a rectangle that is 12 feet x 16 feet?
A rectangle has 2 pairs of equal sides. perimeter is the sum of the lengths of all sides: Perimeter = 12 + 12 + 16 + 16 = 56 Ft Area = 12 x 16 = 192 Ft2
What is the area of a rectangle is the length is 16 and the primeter is 56?
The area of rectangle is : 896.0
